Number of filter taps in Gaussian filter design
27 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello,
I'm desinging a pulse shaping filter where the filter covers a span of 5 inputs symbols and 12 times of input symbol rate (e.g., 3.25 MHz). So I tried to use "gaussdesign" with parameter BT = 0.3, span = 5, and sps = 12.
I was expecting 60 coefficients which can be implemented with a polyphase FIR filter with a total 12 phases. However, the design with "gaussdesign" generated 61 taps. So what's happening here...? Am I missing something?
Thanks,
Jay
0 commentaires
Réponse acceptée
Paul
le 24 Sep 2023
Hi Jay,
"The number of symbols between the start and end of the impulse (span) and the number of samples per symbol (sps) determine the length of the impulse response: span×sps+1."
The impulse response for the given parameters is of length 61 and the number of delays needed to realize such a filter is 60, i.e.,
H(z) = h[0] + h[1]*z^-1 + .... h[60]*z^-60.
So there are 60 "taps," if by tap we mean "delay element."
3 commentaires
Paul
le 24 Sep 2023
I don't why span x sps must be even.
My guess is that it's important to have the impulse response be symmetric around the peak, which can only occur if the duration of the impulse response, span*sps + 1, is odd.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Digital Filter Analysis dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!