Error about Worst performer calculate
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ns=10000;
face=10000;
val_date='2023-09-26';
mid_date= ['2024-03-21';'2024-09-23';'2025-03-21';'2025-09-23';'2026-03-23';'2026-09-18'];
strike=[1.0 0.95 0.9 0.85 0.8 0.75];
c_rate=[0.05 0.1 0.15 0.2 0.25 0.3];
dummy=0.3;
ki=0.5;
ki_YesNO='NO';
ref_S= [9179.5];
S=[6165.71];
r=0.05;
vol=[0.09];
rho=0.37;
temp_ch=datenum(mid_date)'-datenum(val_date);
mid_ch=temp_ch(find(temp_ch>=0));
c_rate=c_rate(find(temp_ch>=0));
strike=strike(find(temp_ch>=0));
N=mid_ch(end);
dt=1/365;
mid_size=length(mid_ch);
payment=zeros(ns,mid_size);
for i =1:ns
for j=1:mid_size
payment(i,j)=face*(1+c_rate(j));
end
end
corr=[1 rho;rho 1];
M=chol(corr);
SP1=zeros(ns,N+1);
SP1(:,1)=S(1);
for i=1:ns
w0=randn(N,2);
w=w0*M;
for j=2:N+1
SP1(i,j)=SP1(i,j-1)*exp((r-vol(1)^2/2)*dt+...
vol(1)*sqrt(dt)*w(j-1,1));
end
end
R1=SP1/ref_S(1);
size(R1)
WP=min(R1)
------------------------------------------
The WP's derivation value should be as many as 10000 simulations, but only one line is derived, so the subsequent analysis process cannot be performed. Please help me
5 commentaires
Image Analyst
le 26 Sep 2023
A 10000*1089 array is a 2-D matrix, not a 1-D vector. I don't know what "draw out" means to you. Do you mean "plot"? Or "extract"? Or something else?
Hyunuk Ha
le 26 Sep 2023
Do you mean draw 1089 lines with 1000 x 1089 matrix?
Basically, you can draw column numbers of lines with matrix data using 'plot(matrixdata)'
Réponses (1)
Shivam Lahoti
le 18 Oct 2023
Hi 형현,
From what I can understand, you expect the Worst performer matrix or WP to be a 10000*1 vector, but you are getting a 1*1089 vector.
In the code that is attached, WP is calculated as min(R1), and R1 is a 10000*1089 matrix. min(R1) calculates the column-wise minimum and hence produces a 1*1089 vector, you might want a row-wise minimum which could be calculated as:
WP = min(R1,[],2);
And the plot function could be leveraged to visualize the same.
I hope this helps.
Regards,
Shivam Lahoti.
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