Plotting variables of continuously array with different colors

1 vue (au cours des 30 derniers jours)
Adi Purwandana
Adi Purwandana le 10 Oct 2023
Hello everyone,
Is it possible to :
(1) Change the value of Station column of this array (excel attached) into ordered rank Station? Anyone knows the code to do this? FYI, the number of stations is in hundreds (I put here for example only 3 stations) so, doing this in loop is preferable solution.
(2) Plot those three Station's profile of variable "s" vs depth from those three stations with different colors of line plots? Anyone knows the code to do this also?
Thank you!

Réponse acceptée

Star Strider
Star Strider le 10 Oct 2023
Modifié(e) : Star Strider le 10 Oct 2023
You can use either unique or findgroups for this to get serial indices —
T1 = readtable('datax.xlsx')
T1 = 17×5 table
Station lon lat depth salinity _______ ______ _____ _____ ________ 2 114.64 -8.16 0 33.995 2 114.64 -8.16 2 33.994 2 114.64 -8.16 4 33.994 2 114.64 -8.16 6 33.993 2 114.64 -8.16 8 33.993 2 114.64 -8.16 10 33.992 7 114.72 -8.16 0 33.976 7 114.72 -8.16 2 33.978 7 114.72 -8.16 4 33.977 7 114.72 -8.16 6 33.977 31 114.8 -8.16 0 33.983 31 114.8 -8.16 2 33.981 31 114.8 -8.16 4 33.981 31 114.8 -8.16 6 33.981 31 114.8 -8.16 8 33.981 31 114.8 -8.16 10 33.98
[Us,ix1,ix2] = unique(T1.Station, 'stable');
T1.Station = ix2
T1 = 17×5 table
Station lon lat depth salinity _______ ______ _____ _____ ________ 1 114.64 -8.16 0 33.995 1 114.64 -8.16 2 33.994 1 114.64 -8.16 4 33.994 1 114.64 -8.16 6 33.993 1 114.64 -8.16 8 33.993 1 114.64 -8.16 10 33.992 2 114.72 -8.16 0 33.976 2 114.72 -8.16 2 33.978 2 114.72 -8.16 4 33.977 2 114.72 -8.16 6 33.977 3 114.8 -8.16 0 33.983 3 114.8 -8.16 2 33.981 3 114.8 -8.16 4 33.981 3 114.8 -8.16 6 33.981 3 114.8 -8.16 8 33.981 3 114.8 -8.16 10 33.98
figure
stem3(T1.Station, T1.depth, T1.salinity, ':k', 'Marker','none')
hold on
scatter3(T1.Station, T1.depth, T1.salinity, 150, T1.salinity, 'p', 'filled')
hold off
xlabel('Station')
ylabel('Depth')
zlabel('Salinity')
xticks(1:3)
This uses the third output of unique to get serial indices (note that I use the 'stable' argument to avoid sorting the results). The findgroups function works similarly to produce a grouping variable. The grouping variable vector is used here as the new value for ‘Station’.
EDIT — Added plots.
.
  12 commentaires
Adi Purwandana
Adi Purwandana le 11 Oct 2023
Modifié(e) : Adi Purwandana le 11 Oct 2023
I think I solved it...
LON(k,:) = StaData{k}.long(1);
Star Strider
Star Strider le 11 Oct 2023
That is correct.
Actually:
LON = StaData{k}.lon(1);
or:
LON(k) = StaData{k}.lon(1);
depending on the result you want.
(I was away for a few minutes running errands.)

Connectez-vous pour commenter.

Plus de réponses (1)

Sulaymon Eshkabilov
Sulaymon Eshkabilov le 10 Oct 2023
Logical indexing would be an easy way of sorting the data and assigning new values to column 'station'. Then use the sorted data indecies to plot the data: s vs. depth
Here is one of the ways of doing it:
F = readmatrix('datax.xlsx');
Idx1=F(:,1)==2;
Idx2=F(:,1)==7;
Idx3=F(:,1)==31;
F(Idx1,1) = 1;
F(Idx2,1) = 2;
F(Idx3,1) = 3;
% Plotting the data
plot(F(Idx1, 5),F(Idx1, 4), '-o','linewidth', 2), hold all
plot(F(Idx2, 5),F(Idx2, 4), '-s','linewidth', 2)
plot(F(Idx3, 5),F(Idx3, 4), '-d','linewidth', 2)
legend('Station: 1', 'Station: 2', 'Station: 3', 'location', 'best')
grid on
xlabel('s')
ylabel('depth')
  1 commentaire
Adi Purwandana
Adi Purwandana le 10 Oct 2023
Thank you @Sulaymon Eshkabilov. It's solved if the number of station is not much. In my case, the number of stations is in hundreds and even thousands. Do you know to do that in something like looping lines to do this?

Connectez-vous pour commenter.

Catégories

En savoir plus sur Resizing and Reshaping Matrices dans Help Center et File Exchange

Produits


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by