![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1509844/image.png)
Why won't my plot start 0 and increase to 0.005 like my Ld
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Aijalon Marsh
le 13 Oct 2023
Modifié(e) : Star Strider
le 13 Oct 2023
Ld=(0:0.001:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
figure
plot(Ld, q, 'o-');
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C", q);
0 commentaires
Réponse acceptée
Star Strider
le 13 Oct 2023
Modifié(e) : Star Strider
le 13 Oct 2023
It does. It just uses the exponent
to scale it.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/1509844/image.png)
Add these lines:
Ax = gca;
Ax.XAxis.Exponent = 0;
to see the tick labels as more obvious decimal fractions, as I did here —
Ld=(0:0.001:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
figure
plot(Ld, q, 'o-');
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C\n", q);
Ax = gca;
Ax.XAxis.Exponent = 0; % <— ADDED
.
0 commentaires
Plus de réponses (1)
KSSV
le 13 Oct 2023
clc; clear all ;
% url = 'https://www.ioc-sealevelmonitoring.org/list.php?operator=&showall=all&output=contacts#' ;
% T = webread(url);
Ld=(0:0.001:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
figure
plot(Ld, q, 'o-');
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C\n", q);
str = cell(length(Ld),1) ;
for i = 1:length(Ld)
str{i} = num2str(Ld(i)) ;
end
xticks(Ld)
xticklabels(str)
0 commentaires
Voir également
Catégories
En savoir plus sur Red dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!