How to mark points at 1-5 on the x-axis in the plot
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Aijalon Marsh
le 13 Oct 2023
Modifié(e) : Star Strider
le 13 Oct 2023
clc;
clear all ;
Ld=(0:0.00005:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
Q=min(q);
figure
plot(Ld, q);
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C\n", Q);
2 commentaires
Dyuman Joshi
le 13 Oct 2023
Modifié(e) : Dyuman Joshi
le 13 Oct 2023
What do you mean by "mark points at 1-5 on the x-axis in the plot"?
Could you give an example of what the expected output is?
Réponse acceptée
Star Strider
le 13 Oct 2023
Modifié(e) : Star Strider
le 13 Oct 2023
One possibility —
clc;
clear all ;
Ld=(0:0.00005:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
Q=min(q);
figure
plot(Ld, q);
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C\n", Q);
xlim([0 6]*1E-3)
Ldq = get(gca,'XTick');
qv = interp1(Ld, q, Ldq);
idx = isfinite(qv);
text(Ldq(idx), qv(idx), compose('Ld = %.3f\nq = %8.3f\n\\downarrow',[Ldq(idx); qv(idx)]'), 'Horiz','left', 'Vert','bottom', 'FontSize',8)
.
0 commentaires
Plus de réponses (1)
Dyuman Joshi
le 13 Oct 2023
Modifié(e) : Dyuman Joshi
le 13 Oct 2023
Ld=(0:0.00005:0.005);
w=0.001;
L=0.007;
P=4*0.001;
Ta=25;
h=375;
Kf=175;
Kd=0.032;
Tb=75;
Ap=3.02*10^-3;
N=238;
Ac=10^-6;
m=92.6;
Lf=L-Ld;
Rtf=(cosh(m.*Lf)+(h./(m.*Kf)).*sinh(m.*Lf))./(sqrt(4*h.*(w)^3*Kf).*(sinh(m.*Lf)+h./(m.*Kf)).*cosh(m.*Lf));
R_fins=Rtf/N;
Rf_cond=Ld/(Kf*N*Ac);
Rd_cond=Ld/(Kd*(Ap-N*Ac));
Ad=Ld./(Kd*Rd_cond);
R_conv=1./(h*Ad);
q=(Tb-Ta)./(Rd_cond+R_conv)+(Tb-Ta)./(Rf_cond+R_fins);
Q=min(q);
figure
p = plot(Ld, q);
xlabel('Dust layer thickness, Ld (m)');
ylabel('Heat Rate, q(W)');
grid on;
fprintf("Total heat rate %.2f°C\n", Q);
Since only 1 data-tip can be added at a time, use a for loop -
%Define the x values to get data-tips for
vec = (1:5)/1e3;
for k=vec
%% Using tolerance to compare floating point numbers
%The highest significant digit of values in Ld is 5, corresponding to
%10^-5 or 1e-5, thus select a tolerance smaller than that
idx = abs(Ld-k)<1e-6;
datatip(p, Ld(idx), q(idx))
end
As the graph is monotonic, there is only 1 y-point corresponding to a single x-point. Thus we can directly use logical-indexing.
For other cases, the code might need modifications.
0 commentaires
Voir également
Catégories
En savoir plus sur Graphics Object Properties dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!

