Effacer les filtres
Effacer les filtres

How to find phase and frequency spectrum of signal?

7 vues (au cours des 30 derniers jours)
Ihor
Ihor le 17 Nov 2023
Commenté : Paul le 17 Nov 2023
I have a signal:
t = -2:0.01:2;
x = zeros(size(t));
x(t >= -2 & t < -1) = -1;
x(t >= 0 & t <= 2) = -1;
how I can find frequency and phase spectrum of this signal? I need to plot all of it.
  1 commentaire
Paul
Paul le 17 Nov 2023
What is the value of x(t) for abs(t) > 2?

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Réponses (1)

Star Strider
Star Strider le 17 Nov 2023
A one-sided fft
t = -2:0.01:2;
x = zeros(size(t));
x(t >= -2 & t < -1) = -1;
x(t >= 0 & t <= 2) = -1;
figure
plot(t, x)
grid
xlabel('t')
ylabel('x')
title('Time Domain Plot of ‘x(t)’')
axis('padded')
Fs = 1/mean(diff(t));
Fn = Fs/2;
L = numel(t);
NFFT = 2^nextpow2(L);
FTx = fft(x(:).*hann(L), NFFT)/L;
Fv = linspace(0, 1, NFFT/2+1)*Fn;
Iv = 1:numel(Fv);
figure
tiledlayout(2,1)
nexttile
plot(Fv, abs(FTx(Iv))*2)
grid
ylabel('Magnitude (absolute)')
nexttile
plot(Fv, unwrap(angle(FTx(Iv))))
grid
xlabel('Frequency (cycles/(time unit))')
ylabel('Phase (rad)')
sgtitle('One-Sided Fourier Transform of ‘x(t)’')
Make appropriate changes to get the result you want.
.
  1 commentaire
Paul
Paul le 17 Nov 2023
Doesn't some adjustment need to be made to the phase to account for the fact that the signal "starts" in negative time, but fft assumes the the first point in the input corresponds to t = 0?

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