Hello, I have a cell array with the list of files I would like to delete. However I would not like to use a for loop to loop through each file to delete it.
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Krishna Ghanakota
le 8 Mar 2024
Commenté : Steve Van Hooser
le 18 Juin 2024
Files - A cell array of size 1x3 with file names to be deleted.
Files =
1×3 cell array
{'1.txt'} {'2.txt'} {'3.txt'}
Working Code :
for i = 1:length(Files)
delete(string(Files(i)));
end
However, I would like to write a single line of code without for loop to achieve the same.
Note: Every run of my code can have different number of files to be deleted. So hardcoding with the command
delete 1.txt 2.txt 3.txt
will not be helpful.
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Réponse acceptée
Voss
le 8 Mar 2024
Modifié(e) : Voss
le 8 Mar 2024
Pass the file names as arguments to delete(). Since the names are already in a cell array, this is easy:
delete(Files{:})
Demonstration:
% make some .txt files:
writematrix(1,'1.txt')
writematrix(2,'2.txt')
writematrix(3,'3.txt')
% get info about the .txt files:
fn = dir('*.txt') % 3 files found
% construct a cell array with the file names:
Files = fullfile({fn.folder},{fn.name});
% delete the files:
delete(Files{:})
% confirm that all three files have been deleted:
fn = dir('*.txt') % 0 files found
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Stephen23
le 18 Juin 2024
Modifié(e) : Stephen23
le 18 Juin 2024
"This use of calling delete with a cell array of file names is not documented but probably should be in the documentation for delete."
This answer does not call DELETE with a cell array of filenames. In fact it calls DELETE with every filename as a separate input, exactly as documented: https://www.mathworks.com/help/matlab/ref/delete.html
This answer uses a comma-separated list generated from a cell array. A comma-separated list is a general syntactical feature of MATLAB that can be used with any function or operator:
Steve Van Hooser
le 18 Juin 2024
Yes, this is correct. Sorry for my error. DELETE does NOT take cell arrays as an input. (I just realized and was coming back to correct myself! You beat me to it.)
Thanks
Steve
Plus de réponses (1)
Chuguang Pan
le 8 Mar 2024
maybe you can use cellfun.
Files={'1.txt','2.txt','3.txt'};
cellfun(@delete,Files)
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