Hello people:
I have the following code:
L=500;
S=ones(1,L);
n=50;
S((L/2-n(i)/2):(L/2+n(i)/2))=0;
I would like to have a matrix M(10,L) where M(1,L) is S when n=50, M(2,L) is S when n=100 and M(3,L) is n=150 and so on...
Does anyone knows how to do it using a loop?
Thank you,
Maria

 Réponse acceptée

Star Strider
Star Strider le 17 Avr 2015
Modifié(e) : Star Strider le 17 Avr 2015

0 votes

With only three iterations, the easiest way is to use a for loop:
L=500;
S=ones(1,L);
M = zeros(10,L);
n = [50, 100, 150];
for i = 1:length(n)
S((L/2-n(i)/2):(L/2+n(i)/2))=0;
M(i,:) = S;
end
EDIT — Inserted ‘M’ preallocation.

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