clear;clc
%%
fc = 3e8;% Carrier frequency
Nb = 1000;% Number of snapshots
c = 3e8;
wavelength = c/fc;% The wavelength of the received signal
d = 0.5*wavelength;
theta = [5 40];
M = length(theta);% Number of signals
N = 10;% Number of antennas
% Wavenumber
beta = 2*pi/wavelength;
% Signal amplitude
A = 1;
% SNR (dB)
snr = 5;
% Variance of noise
sigma=sqrt((A^2)/(2*10^(snr/10)));
% Source signal
D = randi(M,Nb,1);
S =A*(2*D - 1);
% The electrical phase shift from element to element along the array
phi=beta*d*cos(theta*pi/180);
% Matrix of steering vectors
for i=1:M
for k=1:N;
VecteurDirectionnel(k,i)= exp(j*(k-1)*phi(i));
end
end
% White Gaussien noise
B = (sigma^2)*(randn(N,Nb)+j*randn(N,Nb))/sqrt(2);
% Array output:signal plus noise
X = VecteurDirectionnel*S+B;
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix individually, use TIMES (.*) for elementwise multiplication.
% Estimation of the spatial correlation matrix of the observed signal
Rxx = X*X'/Nb;
% Eigen decomposition
[Vi,Li] = eig(Rxx);
[L,I] = sort(diag(Li),'descend');
V = Vi(:,I);
Vs = V(:,1:M);
Vs1=Vs(1:N-1,:);
Vs2=Vs(2:N,:);
% Direction Of Arrival
% Least square
xsi=linsolve(Vs(1:N-1,:),Vs(2:N,:));
% DOA estimation
doa=acosd((angle(eig(xsi))/(2*pi*d)))

 Réponse acceptée

Matt J
Matt J le 16 Avr 2024
Modifié(e) : Matt J le 16 Avr 2024
As you can see, VecteurDirectionnel and S are the wrong sizes for matrix multiplication,
whos VecteurDirectionnel S
Name Size Bytes Class Attributes S 1000x1 8000 double VecteurDirectionnel 10x2 320 double complex
% Array output:signal plus noise
X = VecteurDirectionnel*S+B;
Error using *
Incorrect dimensions for matrix multiplication. Check that the number of columns in the first matrix matches the number of rows in the second matrix. To operate on each element of the matrix individually, use TIMES (.*) for elementwise multiplication.

6 commentaires

Sadiq Akbar
Sadiq Akbar le 16 Avr 2024
Thanks a lot for your kind response. Yes, but how will we correct it?
Stephen23
Stephen23 le 16 Avr 2024
"but how will we correct it?"
We cannot guess what you expect the output of "multiplying" a 1000x1 matrix with a 10x2 matrix to be.
Please tell us the exact size you expect the result of that operation to be.
Matt J
Matt J le 16 Avr 2024
@Sadiq Akbar In addition to what Stephen said, you should know what sizes you expect VecteurDirectionnel and S themselves to be. You should be able to tell us what is wrong.
Sadiq Akbar
Sadiq Akbar le 19 Avr 2024
Thanks to both of you for your kind responses. Actualy the sizes of the matrices VecteurDirectionnel and S should be 10 x 2 and 2 x 1000 respectively. But I don't know how to make size of S as 2 x 1000?
Well S is Nb x 1 because D is Nb x 1, from this line,
D = randi(M,Nb,1);
Perhaps you meant to have,
D = randi([low, hi] , [M,Nb]);
but we have no way of knowing what you intended the low and hi limits to be.
Sadiq Akbar
Sadiq Akbar le 22 Avr 2024
Thanks a lot for your help. Yes, you are right. It works now.

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