how to use an integral function inside a for loop? i need to find the value of function that chages as i chages .then using this values i need to find another integral.
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r0 =0.1
u =[1:7]'
Q =zeros(length(u),1)
E =zeros(length(Q),1)
for i =1:length(u)
Q(i,1) =0.023*(r0^(-1/4))*((u(i))^(-14/4))
f =@(Q) (Q(i)).^(0.3)
E(i,1) =integral(f,1,7)
end
3 commentaires
Torsten
le 5 Juin 2024
E(u1)= integral from u0 to u2 [Q(u)^(0.3)]du
You define E as a function of u1, but u1 does not appear on the right-hand side.
Réponses (1)
Alan Stevens
le 5 Juin 2024
Are you looking for something like this?
r0 =0.1;
u =[1:7]';
Q =zeros(length(u),1);
E =zeros(length(Q),1);
Q = @(x)0.023*(r0^(-1/4))*(x.^(-14/4));
f = @(x) Q(x).^0.3;
for i =1:length(u)
u0 = 1; u2 = u(i);
E(i,1) =integral(f,u0,u2);
end
disp(E)
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