increasing precison using fprintf for text file
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
cellArray =
[ 334] [38.141794059793398] [31.983184186130529] [1.751451095529832e+03]
[ 352] [38.094455446389709] [31.940682658186898] [1.779530219110660e+03]
[ 404] [38.162956465159276] [32.019563510560964] [1.542875077314675e+03]
[ 414] [38.176654734516106] [32.068817577008474] [1.389497182917781e+03]
[ 476] [38.075635175382899] [32.027977260576755] [1.994276513063349e+03]
[2729] [38.229399882994215] [31.934421897750756] [1.167495300253853e+03]
[2730] [38.205404821919039] [31.911611428797361] [1.291408437962644e+03]
[2742] [38.104502101643973] [31.931891003528762] [1.774978352412581e+03]
Name Size Bytes Class Attributes
cellArray 8x4 3840 cell global
% I use below codes to write cellArray into txt file
startingFolder='C:\Program Files\MATLAB';
if ~exist(startingFolder, 'dir');
startingFolder = pwd;
end
defaultFileName=fullfile(startingFolder, '*.txt');
[baseFileName, folder]=uiputfile(defaultFileName, 'Select a file');
if baseFileName == 0
return
end
fullFileName = fullfile(folder, baseFileName);
c=cellfun(@num2str,cellArray,'un',0);
[n,m]=size(c);
form=[repmat('%s ',1,m) ' \r\n'];
fid = fopen(fullFileName, 'w');
for k=1:n
fprintf(fid, form, c{k,:});
end
fclose(fid);
% but data (2-3-4rd columns) are written only 4 numbers after the comma (like, 38.1418). I need to write the data into txt file without rounding.
3 commentaires
per isakson
le 23 Avr 2015
Modifié(e) : per isakson
le 23 Avr 2015
Replace
@num2str
by
@(str) num2str( str, format_specifier )
or better
>> cellfun( @num2str, {123,34567/3}, {'%d','%18.12f'}, 'uni', false )
ans =
'123' '11522.333333333334'
Réponse acceptée
Star Strider
le 23 Avr 2015
If you need full precision on all numeric variables and want to use repmat to create your ‘form’ format descriptors, instead of %s, I would use %23.15E. That will print all of them out to full precision.
7 commentaires
Star Strider
le 23 Avr 2015
No worries.
The only change I suggested is to use this assignment for ‘form’:
form = '%5d %23.15E %23.15E %23.15E\n';
Experiment with it to see if it works to your satisfaction.
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Language Support dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!