How to give range of cells different variable names?
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Hello!
I am collecting data from a range of cells from an .xlsx file using the readmatrix function as so:
Datafiles(j).data = readmatrix(Data,'Sheet','Report','Range','M18:N18','FileType','spreadsheet');
Then I populate that data into a new excel file like so:
CurrentData = {Datafiles.data}';
TABLE_Pass = table(CurrentData);
TABLE = vertcat(TABLE_Pass);
Now, my problem is, it spits out the data in 2 columns labeled "CurrentData_1" "CurrentData_2" and I want to specify the name of the second column.
When I create a second variable name, it gives me 4 columns with the information doubled.
Any tips on how to give the data 2 separate variable names?
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Star Strider
le 12 Août 2024
It might help to have the file.
Otherwise, conbbsider specifying the variable names as (for example):
TABLE.Properties.VariableNames = {'Variable Name 1','Variable Name 2'}
of course using the varialbe names you want to assign to them.
.
4 commentaires
Star Strider
le 13 Août 2024
I don’t know what they should be called, however this is how to change their names. Insert the correct names for ‘Column 1’ and ‘Column 2’. (In R2023b, spaces and some other special characters are permitted.)
Data = 'CurrentData.xlsx';
data = readtable(Data)
data.Properties.VariableNames = {'Column 1','Column 2'}
.
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Voss
le 12 Août 2024
Try replacing this
CurrentData = {Datafiles.data}';
TABLE_Pass = table(CurrentData);
TABLE = vertcat(TABLE_Pass);
with this
CurrentData = vertcat(Datafiles.data);
TABLE = array2table(CurrentData,'VariableNames',{'x','y'});
and replace 'x' and 'y' with the variable names you want to use.
2 commentaires
Voss
le 13 Août 2024
Don't create a cell array of 1-by-2 vectors by doing this:
CurrentData = {Datafiles.data}';
because that will lead to a table with one variable, which is a cell array of 1-by-2 vectors.
Instead, create an N-by-2 matrix by doing what I showed in my answer:
CurrentData = vertcat(Datafiles.data);
because that will lead to a table with two variables, which you can name individually.
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