Skipping Optional Positional Arguments
50 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I am writing a routine that uses arguments to parse input parameters. After many years of using both inputParser and manual input parsing, I like using arguments. However, I seem to be running into some limitations.
I am trying to get arguments to ignore an optional positional arguments. Take the example function:
function y = foo(a,b,c)
arguments
a
b = 2
c = 3
end
y = a + b + c;
end
Suppose I want to specify arguments for a and c and use the default value of b. With manual parsing, I would just detect an empty value for b by calling foo(1,[],3). When using arguments, I can not achieve the same functionality by calling as foo(1,~,3) or similar syntax.
Is there a way to get this functionality without resorting to manual parsing?
2 commentaires
Stephen23
le 25 Oct 2024 à 23:27
"Is there a way to get this functionality without resorting to manual parsing?"
Not as far as I am aware. You should make an enhancement suggestion here:
Réponses (3)
Star Strider
le 25 Oct 2024 à 23:36
To illustrate —
out = foo(1,pi,3)
out = foo(1,[],3)
out = foo(1,~,3)
function y = foo(a,varargin)
optargs = cell(1,2);
optargs(1:numel(varargin)) = varargin;
if isempty(optargs{1})
b = 2;
else
b = optargs{1};
end
if isempty(optargs{2})
c = 3;
else
c = optargs{2};
end
y = a + b + c;
end
Not everything is possible.
.
0 commentaires
Walter Roberson
le 26 Oct 2024 à 3:53
Unfortunately you cannot use [] to trigger detection as "missing" for the purpose of default argument processing.
function y = foo(a,b,c)
arguments
a
b double {mustBeEmptyOrNumeric(b)} = 2
c = 3
end
if isempty(b); b = 2; end
y = a + b + c;
end
function mustBeEmptyOrNumeric(b)
if ~isempty(b) && ~isnumeric(b)
eidType = 'mustBeEmptyOrNumeric:notEmptyOrNumeric';
msgType = 'Input must be empty or numeric.';
error(eidType, msgType);
end
end
0 commentaires
埃博拉酱
le 26 Oct 2024 à 15:02
It is recommended that you use name-value arguments:
function y = foo(a,options)
arguments
a
options.b = 2
options.c = 3
end
y = a + b + c;
end
Then you can specify c without b:
foo(1,c=3);
0 commentaires
Voir également
Catégories
En savoir plus sur Argument Definitions dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!