Populating a tiledlayout vertically rather than horizontally

Hi, I have an 1D array of images in a cell array.

I want to montage them using my own settings, so I have been using tiledlayout.

I must have 3 rows, and my total number of images is always a multiple of 3.

n=app.ImCount.Value;   % number of images in my cell array
tcl = tiledlayout(3,ceil(n/3),'TileSpacing','none','Padding','compact');   %tight 
 for i=1:n  
    IM=app.imgArray{i};                
    ROI=imcrop(IM,rect);
    ax=nexttile(tcl);
    myImagesc(app,ax,ROI); axis(ax,'image');
 end               

Say I have 12 images, rather than have the layout like this:

1 2 3 4
5 6 7 8
9 10 11 12

I want this, i.e. populating vertically

1 4 7 10
2 5 8 11 
3 6 9 12

I thought there might have been an option in the tied layout but there is only a complete "vertical" arrangement possible.

So my idea next is to just index the images like 1,4,7,10,2,5,8,11 etc, but have no idea how to do this or whether this is a good way anyway

Thanks

Answer 1

[Star Strider]

One option could be to use the TileIndexing property, and set it to 'columnmajor'.

[Jason]

thats exactly what Im looking for, but didn't see it.

Thnaks

[Star Strider]

As always, my pleasure!

[Jason]

out of interest do you have any suggestions to to link my counter i to the order:1 4 7 10 2 5 8 11 3 6 9 12?

[Star Strider]

I am not quite certain what you want to do.

To create a row vector with those values --

v = reshape(reshape(1:12, 3, []).', 1, [])

v = 1×12

1 4 7 10 2 5 8 11 3 6 9 12

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and a column vector --

v = reshape(reshape(1:12, 3, []).', [], 1)

v = 12×1

1 4 7 10 2 5 8 11 3 6 9 12

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The counter would then index into it as:

for k = 1:numel(v)
    fprintf('Index %2d = v(%2d)\n', k, v(k))
end

Index  1 = v( 1)
Index  2 = v( 4)
Index  3 = v( 7)
Index  4 = v(10)
Index  5 = v( 2)
Index  6 = v( 5)
Index  7 = v( 8)
Index  8 = v(11)
Index  9 = v( 3)
Index 10 = v( 6)
Index 11 = v( 9)
Index 12 = v(12)

If you want something else, please describe it in a bit more detail.

.

[Jason]

Thats perfect, thankyou once again!

[Star Strider]

As always, my pleasure!