How do I change column headers in my table

8 vues (au cours des 30 derniers jours)
Scott Banks
Scott Banks le 26 Août 2025
Commenté : Star Strider le 26 Août 2025
I have some data that I am displaying in my script and have outputted it in 28 different tables. My script is quite long so I am just posting a screenshot for now.
Where is says var 2 I want to change to the storey number. So for table 1 I want storey 1, for table 2, storey 2 etc...
If you can see for the main output i am running a loop and using the matrix called "Int_force". I also have made the row headers as [Axial Force, Shear Force, Bending Moment. Thus, I am hoping someone can help me so that I can change the column headers to my desired wish? I am not sure how I would change the loop to accomplish this.
Many thanks,
Scott
  1 commentaire
Torsten
Torsten le 26 Août 2025
You overwrite tables 1-27 in your loop and you are left with table 28.

Connectez-vous pour commenter.

Réponse acceptée

Star Strider
Star Strider le 26 Août 2025
If your immediate problem is naming the variables, perhaps --
Int_force = randn(6,6,28);
Force = repmat(["Axial Force";"Shear Force";"Bending Moment"],2,1);
for ii = 1:28
T{:,ii} = table(Force,Int_force(:,:,ii), VariableNames=["Force","Storey "+ii]);
end
T{1:3}
ans = 6×2 table
Force Storey 1 ________________ ____________________________________________________________________ "Axial Force" 0.25824 -1.0666 0.52455 0.061362 0.83612 -0.57872 "Shear Force" -0.33978 -0.677 0.08896 -0.55037 -1.9187 0.052839 "Bending Moment" -0.68629 -0.77981 0.52746 -0.6832 0.45266 0.13577 "Axial Force" 0.97137 2.5555 0.16246 1.1639 1.7025 -0.40126 "Shear Force" -1.3975 -0.23952 -2.0119 1.1432 -0.26792 2.2068 "Bending Moment" -1.4253 0.063041 -2.4109 0.26882 -0.90365 0.049716
ans = 6×2 table
Force Storey 2 ________________ _________________________________________________________________________ "Axial Force" -1.1477 0.6543 -0.14317 -0.039486 1.4339 -1.264 "Shear Force" -0.42278 -0.054125 -0.022768 0.5618 -0.078847 0.91655 "Bending Moment" -2.3065 -0.2194 -0.25508 1.2181 -0.1286 -1.2847 "Axial Force" -2.0327 1.8675 -2.0148 0.52304 0.49065 0.072621 "Shear Force" -0.29637 0.082269 1.2084 0.72773 2.039 -1.5388 "Bending Moment" -0.24284 -2.3689 -0.67396 0.36504 -0.58589 0.82584
ans = 6×2 table
Force Storey 3 ________________ _________________________________________________________________________ "Axial Force" 0.45866 -0.43073 0.18425 -0.22845 0.81357 -1.0366 "Shear Force" 0.39192 -0.052734 0.6977 0.09103 -0.42306 -1.1206 "Bending Moment" 0.061773 -0.91316 0.651 0.23485 -0.11815 -1.2856 "Axial Force" 2.1351 0.69848 -0.19996 -0.77539 2.8288 0.31379 "Shear Force" 1.9178 -1.041 0.0087346 -1.2634 0.10913 -0.33258 "Bending Moment" 0.31495 -1.8692 0.97796 -0.82828 -0.8282 -0.29363
Note that 'T' was being overwritten in every iteration of the loop, so I created a cell array of them.
Make appropriate changes to get the result you want.
.
  4 commentaires
Scott Banks
Scott Banks le 26 Août 2025
Thank you once again, Star Strider
Star Strider
Star Strider le 26 Août 2025
As always, my pleasure!

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Dates and Time dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by