Binary to DNA sequence encoding - matlab

I am implementing DNA encryption algorithm.
For that, I have a vector containing binary values such as:
01100011 01110010 01111001 01110000 01110100 01101111.
Now, these values should be mapped to DNA sequence. How do I do that in MATLAB?

2 commentaires

Star Strider
Star Strider le 20 Sep 2015
DNA has four bases (two complementary sets, A-T and C-G) and you have a binary sequence ...
Meghashree G
Meghashree G le 20 Sep 2015
yeah..i know To use ATGC concept,but i don't know how to code..Like how do i extract only 2 digits from the binary vector and assign it to either A,T,G,C..

Connectez-vous pour commenter.

 Réponse acceptée

Image Analyst
Image Analyst le 20 Sep 2015
Perhaps this:
% Assign sample data.
binaryArray = [0,1,1,0,0,0,1,1, 0,1,1,1,0,0,1,0, 0,1,1,1,1,0,0,1, 0,1,1,1,0,0,0,0, 0,1,1,1,0,1,0,0, 0,1,1,0,1,1,1,1];
% Define base letters to choose from.
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
% Display in command window:
result
It shows:
result =
TGACTCAGTCGTTCAATCTATGCC

12 commentaires

Meghashree G
Meghashree G le 20 Sep 2015
Thank you so much :) it worked :)
Saurabh Kumar
Saurabh Kumar le 12 Fév 2018
I want to create a function in Matlab of above solution you have given. So that I don't need to describe different binary Everytime in .m blank file format. Please help Function []=binary()
function result = LabelBinaryArray(binaryArray)
% Define base letters to choose from.
bases = 'ATGC';
for k = 1 : 2 : length(binaryArray)
% Convert these two digits into a number 1 - 4.
index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
% Use that index to assign a letter to our result.
result((k+1)/2) = bases(index);
end
Saurabh Kumar
Saurabh Kumar le 12 Fév 2018
Attempted to access binaryArray(2); index out of bounds because numel(binaryArray)=1.
Error in LabelBinaryArray (line 6) index = 2 * binaryArray(k) + binaryArray(k+1) + 1;
NOT WORKING
Image Analyst
Image Analyst le 12 Fév 2018
It works if you pass in something like you said, like '01100011'. You can't pass in a single value like '1' like you did because that can't be mapped to a letter. How do I know you passed in only a single element? Because the error message says "because numel(binaryArray)=1" Are you sure you're passing in a binary array like you said? I'm assuming a binary array, which is class logical, though a double will work. You aren't passing in a string are you? Show me how you defined the array you passed in to the function.
LabelBinaryArray('011000110111001001111001011100000111010001101111')
Attempted to access bases(146); index out of bounds because numel(bases)=4.
Error in LabelBinaryArray (line 8) result((k+1)/2) = bases(index);
OK, you have a string, not a binary/logical array. To convert to a binary array you need to do this:
str = '011000110111001001111001011100000111010001101111'
binaryArray = logical(str - '0')
You can do that either inside the function, if you want to pass a string, or in your main program before you call the function, if you want to pass a binary array.
Saurabh Kumar
Saurabh Kumar le 13 Fév 2018
it worked. THANKS
How to decrypt it back to binary sequence
Image Analyst
Image Analyst le 5 Déc 2020
Decrypt what back to a binary sequence. You have the binary sequence both as a character array, str, and a logical/boolean array, binaryArray. What else do you want? What's missing? Just keep both things and you're all set.
Shiva Reddy
Shiva Reddy le 5 Fév 2021
Pls Can I get the decryption code
Image Analyst
Image Analyst le 5 Fév 2021
Shiva, I'm not sure who you're asking, but personally I don't have any to give you.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Genomics and Next Generation Sequencing dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by