Create moving average filter

6 vues (au cours des 30 derniers jours)
LM
LM le 26 Déc 2011
Hi, I need some help in writing a code for the moving average filter but without using any of the existing matlab functions. It's going to be applied to black and white images, 256x256 pixels, with N rows and M columns:
f(i,j), i=1,2,,N and j=1,2,,M f(i,j)=[0,255]
If the function is applied to each of the rows of the image, represented by the array:
[f1 f2 f3 fk-1 fk fk+1 fM]
And with the corresponding exit array:
[g1 g2 g3 gk-1 gk gk+1 gM]
How to solve this, in order to create the moving average filter?:
gk=(agk-1+bgk+cgk+1)/(a+b+c) for k=2,3,,M-1 and a=b=c=1
(and to make sure the length of the arrays is the same, g1= f1 e gM = fM )
Thankyou
  2 commentaires
bym
bym le 26 Déc 2011
"without using any of the existing matlab functions" is vague
LM
LM le 26 Déc 2011
Sorry, I mean the filter function.

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Réponses (2)

Image Analyst
Image Analyst le 26 Déc 2011
Sounds like a class assignment. Think about it. Do you think you could do it with 4 for loops? Maybe one pair that visits every pixel in the image (iterates over rows and columns), and another pair inside that visits every pixel in your NxM window that is centered over the pixel you're visiting?
  1 commentaire
LM
LM le 26 Déc 2011
Yes, I wasn't sure on the structure I should use here, but thanks for your suggestion, I'll try to do it :)

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Jan
Jan le 26 Déc 2011
The moving average can be calculated for the columns at first and the rows afterwards.
For the moving average along the rows or columns a single loop is sufficient: One vector is added to the accumulator and one vector is subtracted.
  2 commentaires
Walter Roberson
Walter Roberson le 26 Déc 2011
Though that does have the disadvantage of having cumulative round-off error.
Jan
Jan le 26 Déc 2011
@Walter: That's correct, but for a 256x256 pixel image this will very likely not matter. If it is a 8 bit grey scale or 8x3 bit RGB image: Using an accumulator of type DOUBLE will be sufficient - as long as the picture are small enough.

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