How do I get these matrix dimensions to match using linspace?
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Joseph Ravenscroft
le 18 Oct 2015
Commenté : Star Strider
le 18 Oct 2015
I am trying to write an audio algorithm to ramp up the amplitude of a .wav file but I am having problems getting getting the matrix dimensions to match in this line:
processed_waveform = input_waveform.*linspace(0, 1, length(input_waveform));
The error reads as follows:
Error using .*
Matrix dimensions must agree.
Error in Ex_1D (line 41)
processed_waveform = input_waveform.*linspace(0, 1, length(input_waveform));
I have tried using size() in place of length() but I still get the same issue. Any ideas? Thanks
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Star Strider
le 18 Oct 2015
Most audio files are column vectors, and linspace produces a row vector.
Try this:
processed_waveform = input_waveform.*linspace(0, 1, length(input_waveform))';
Transposing the linspace vector should make them compatible. If ‘input_waveform’ is a two-column matrix (two-channel sound file), the code becomes:
processed_waveform = input_waveform.*[linspace(0, 1, length(input_waveform))', linspace(0, 1, length(input_waveform))'];
2 commentaires
dpb
le 18 Oct 2015
I've long thought (and made the suggestion at least once as enhancement request) TMW should enhance this error message to explicitly note the orientation mismatch as a possbility when size(OP1)==size(OP2).' as the error occurs so often and the present missive, while correct, clearly doesn't provide guidance enough in many (most?) cases...
Star Strider
le 18 Oct 2015
Allowing a size argument that would automatically orient and replicate the resulting vector would be helpful, but we’re not there yet.
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