Building a matrix with a for-loop
12 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello, I am constructing a matrix using the following program:
%Program HW13.m
x = 35;
y = 26;
n = 5;
for i = 1:1:n+1
x(i+1) = 18*x(i) - 11*y(i);
y(i+1) = 8*x(i) - y(i);
end
The for-loop generates two matrices, one for "x" and one for "y". However, I need to create new matrix: column 1 with the "i" values, column 2 with the iterated "x" values, column 3 with the iterated "y" values, and column 4 with "x/y" values. Any suggestions on how to do this?
0 commentaires
Réponses (2)
Walter Roberson
le 25 Oct 2015
[(1:n+1).', x(:), y(:), x(:)./y(:)]
2 commentaires
Star Strider
le 25 Oct 2015
That should be:
[(1:n+2).', x(:), y(:), x(:)./y(:)]
because of the way the indices work, so the number of elements is n+1+1.
Andrei Bobrov
le 25 Oct 2015
n = 5;
out = zeros(n+2,4);
out(1,2) = 35;
out(1,3) = 26;
for ii = 1:n+1
out(ii+1,2) = 18*out(ii,2) - 11*out(ii,3);
out(ii+1,3) = 8*out(ii,2) - out(ii,3);
end
out(:,1) = 1:n+2;
out(:,end) = out(:,2)./out(:,3);
3 commentaires
Andrei Bobrov
le 25 Oct 2015
>> format short g
>> out
out =
1 35 26 1.3462
2 344 254 1.3543
3 3398 2498 1.3603
4 33686 24686 1.3646
5 3.348e+05 2.448e+05 1.3676
6 3.3336e+06 2.4336e+06 1.3698
7 3.3235e+07 2.4235e+07 1.3714
Voir également
Catégories
En savoir plus sur Operators and Elementary Operations dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!