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Converting Cell Array Output to Logical Matrix

Asked by eugene479 on 19 Jan 2016
Latest activity Commented on by Star Strider
on 20 Jan 2016
I have an array output consisting of the following characters: "A1a", "A1b", "A2a", "A2b" for e.g.:
'A1a' 'A2a'
'A1a' 'A2b'
'A1b' 'A2a'
'A1b' 'A2b'
How do I convert it to a logical matrix such that, if the output contains the character "A1a", under the column "A1a", the value will be true" i.e. "1" ?
%Output
Row A1a A1b A2a A2b
1 1 0 1 0
2 1 0 0 1
3 0 1 1 0
4 0 1 0 1

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2 Answers

Answer by Star Strider
on 20 Jan 2016
Edited by Star Strider
on 20 Jan 2016
 Accepted Answer

This works:
C = {'A1a' 'A2a'
'A1a' 'A2b'
'A1b' 'A2a'
'A1b' 'A2b'};
Cu = unique(C,'stable');
for k1 = 1:length(Cu)
L{k1} = cellfun(@(x) strcmpi(x,Cu(k1)), C);
N(:,:,k1) = L{k1};
end
T = squeeze(sum(N,2));
fprintf(1,'\n\tRow\t%3s\t%3s\t%3s\t%3s\n', Cu{:})
fprintf(1, '\t%2.0f\t%2.0f\t%2.0f\t%2.0f\t%2.0f\n', [[1:4]' T]')
Row A1a A1b A2a A2b
1 1 0 1 0
2 1 0 0 1
3 0 1 1 0
4 0 1 0 1

  2 Comments

Thank you so much! It works great!
My pleasure!

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Answer by Harsheel
on 19 Jan 2016
Edited by Harsheel
on 19 Jan 2016

out = cellfun(@(x)(strcmp(x,'A1a')), A); % A is the input cell array

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