when i apply limit(x^3-​6*(x-sin(x​)))/(6*(x^​4)*sin(x))​, i am getting: ans = 0; but correct ans. is 1/120; Am i doing something wrong?can i replace x by theta?

5 vues (au cours des 30 derniers jours)
when i apply
limit(x^3-6*(x-sin(x)))/(6*(x^4)*sin(x))
i am getting: ans = 0; but correct ans. is 1/120; Am i doing something wrong? can i replace x by theta to get the same value:1/120

Réponse acceptée

Triveni
Triveni le 26 Jan 2016
syms x
a = limit(( (x^3)- 6* (x - sin(x)))/(6* ((x^4))* sin(x)))
  3 commentaires
Walter Roberson
Walter Roberson le 28 Jan 2016
That is, some of your () were misplaced.
Triveni
Triveni le 9 Fév 2016
Actually tried limit(x^3-6*(x-sin(x))) upon (6*(x^4)*sin(x)) and question was
limit([( (x^3)- 6* (x - sin(x)))/(6* ((x^4))* sin(x))])
check [] in equation.

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