Effacer les filtres
Effacer les filtres

how can i find same values in an array?

133 vues (au cours des 30 derniers jours)
suchismita
suchismita le 5 Fév 2016
I have an array a, where
a=[303.1093
94.5581
86.6591
108.1389
303.1093
107.4338
138.6919
106.8294
108.1389
149.3491
187.8940
125.0922
96.7580
303.1093
75.9192
96.2085
118.8788
303.1093
303.1093
303.1093]
then i wanna do
b=round(a);
In b I want to find the positions who are having same values and I want to mark those value as 1 and others 0.
please help me.
Thank you
-- Suchi
  2 commentaires
Meghana Dinesh
Meghana Dinesh le 5 Fév 2016
Modifié(e) : Meghana Dinesh le 5 Fév 2016
How much "similar"? Or do you mean "same"?
suchismita
suchismita le 5 Fév 2016
Modifié(e) : suchismita le 5 Fév 2016
yes same values

Connectez-vous pour commenter.

Réponse acceptée

Star Strider
Star Strider le 5 Fév 2016
Modifié(e) : Star Strider le 5 Fév 2016
The unique function will obviously provide the information you want, but ‘the positions who are having similar values’ is less clear. I believe the au (unique values in ‘a’) and ‘ic’ values (the indices in ‘a’ that correspond to them) is what you want:
[au,ia,ic] = unique(round(a),'stable')
EDIT —
‘I wanna mark those same values as 1 and others 0’
I believe this does what you want:
[au,ia] = unique(round(a),'stable');
Same = ones(size(a));
Same(ia) = 0;
Result = [a Same]
Result =
303.11 0
94.558 0
86.659 0
108.14 0
303.11 1
107.43 0
138.69 0
106.83 1
108.14 1
149.35 0
187.89 0
125.09 0
96.758 0
303.11 1
75.919 0
96.209 0
118.88 0
303.11 1
303.11 1
303.11 1
-
  4 commentaires
Star Strider
Star Strider le 5 Fév 2016
I wasn’t certain what you wanted. I thought you only wanted to flag the repeated values, other than the first occurrence. Since this now seems to be resolved, I’ll not pursue it further.
Stephen23
Stephen23 le 5 Fév 2016
Good point about the "first occurrence". This did not occur to me, and the original question is ambiguous on this point.

Connectez-vous pour commenter.

Plus de réponses (3)

Stephen23
Stephen23 le 5 Fév 2016
This identifies all matching rounded values, unlike the accepted answer:
b = round(a(:));
c = bsxfun(@eq,b,b.');
x = any(tril(c,-1)|triu(c,1),1);
[a(:),+x(:)]
303.1093 1
94.5581 0
86.6591 0
108.1389 1
303.1093 1
107.4338 1
138.6919 0
106.8294 1
108.1389 1
149.3491 0
187.8940 0
125.0922 0
96.7580 0
303.1093 1
75.9192 0
96.2085 0
118.8788 0
303.1093 1
303.1093 1
303.1093 1
  1 commentaire
suchismita
suchismita le 6 Fév 2016
i want to accept your answer but i dont how to unlike the already accepted answer?

Connectez-vous pour commenter.


Bhavini Sarkar
Bhavini Sarkar le 17 Sep 2016
To find the duplicate elements of an array, first you should sort array . After sorting all duplicate elements will aggregate in adjacent positions. Now using a for loop , traverse sorted array and compare adjacent elements. If adjacent elements are equal then you found one duplicate element of array . We can also find duplicate elements of an array in linear time using some extra space.

Azzi Abdelmalek
Azzi Abdelmalek le 5 Fév 2016
[ii,jj,kk]=unique(a,'stable')
  1 commentaire
suchismita
suchismita le 5 Fév 2016
I wanna mark those same values as 1 and others 0, how can i do that

Connectez-vous pour commenter.

Catégories

En savoir plus sur Multidimensional Arrays dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by