Using epsilon in legend

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Hasib Rahman
Hasib Rahman le 18 Fév 2016
Modifié(e) : Deke Cisco le 20 Juil 2024
I want to use Greek symbol epsilon "ɛ" in my legend and I use \epsilon. But it gives me "є" . I found a solution using char(949). But I can not use subscript with that. Actually I need to write "ɛ_21". Can anyone please help me?

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Star Strider
Star Strider le 18 Fév 2016
You just need to concatenate the special character with the subscript, and it works (at least in R2015b):
figure(1)
plot(1:10, rand(1,10))
legend([char(949) '_{21}'])
  3 commentaires
Star Strider
Star Strider le 18 Fév 2016
My pleasure!
Deke Cisco
Deke Cisco le 20 Juil 2024
Modifié(e) : Deke Cisco le 20 Juil 2024
What if you what \varepsilon in the middle of a title? is that possible? Something like this?
title('\sigma_{longitudinal} - '[char(949) '_{longitudinal}'],'FontSize',14)
I'm not a fan of using 'Intepreter','LaTex' because it changes the font, so I'm curious if there is another way. Thank you!

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Plus de réponses (2)

Chad Greene
Chad Greene le 18 Fév 2016
Try this:
title(' $\varepsilon_{21}$ ','interpreter','latex')
  2 commentaires
Chad Greene
Chad Greene le 18 Fév 2016
Ah, you said legend. There's an extra step for legends:
l = legend('$\varepsilon_{21}$');
set(l,'interpreter','latex')
Hasib Rahman
Hasib Rahman le 18 Fév 2016
Thanks Chad. It also works!

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Maria Erans Moreno
Maria Erans Moreno le 21 Août 2019
I have a new question in this topic I need to put ɛ' and ɛ'' in two different graphs
I have tried [char(949) ' ' '] or [char(949) ' " ']
I have also tried with \varepsilon but it does not seem to work. Can somebody help me?
  1 commentaire
ztjona
ztjona le 26 Mai 2022
You just change the interpreter to latex in any function you need (like title, ylabel, legend, etc.) and you can use both epsilons variations.
plot(rand(100, 1))
title('$\epsilon$ and $\varepsilon$', 'Interpreter','latex')

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