Effacer les filtres
Effacer les filtres

Hi i am getting Index out of bounds error pls help me solve it

4 vues (au cours des 30 derniers jours)
Serena Woolridge
Serena Woolridge le 31 Mar 2016
Commenté : Star Strider le 4 Avr 2016
I hv a 2d image of 93×58 pixels. Error im gettin is attempted to access b(1,59) because size(b)=(93,58).
How do i go about rectifying this error?? Pls help as im new to matlab and to image processing. Thanks in advance.
  2 commentaires
Serena Woolridge
Serena Woolridge le 1 Avr 2016
Hi i understand that i im attempting to get a 59th column but i would like to know how i can change my code to rectify it.Pls help.
my code goes like..
for ii=1:m2
for jj=1:n2
x=(b(ii,jj) /100)*(mapsize*mapsize);
end
end
Serena Woolridge
Serena Woolridge le 4 Avr 2016
To make it more clear, i am attempting to split pixels into subpixels of my image of size(93x58) and assign 1s and 0s to the subpixels in order to classify my image into its various classes. The error keeps appearing in the loc:
x=(b(ii,jj)/100)*(ms*ms);
The code i use is:
a=imread('image path');
imshow(a);
[m1,n1,o1]=size(a);
ms=input('enter map size');
m2=m1*ms;
n2=n1*ms;
for ii=1:m2
for jj=1:n2
x=(b(ii,jj)/100)*(ms*ms);
x=round(x);
if(x==(ms*ms))
for n=1:(ms*ms)
mat(n)=1;
end
else
r=randi(1,ms*ms,ms*ms);
d=magic(ms);
for n=1:x
mat(d(n))=1;
end
for n=x+1:(ms*ms)
mat(d(n))=0;
end
end
end
Please help me clear this error in order for me to do my project work. Thanks in advance.

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Réponse acceptée

Star Strider
Star Strider le 31 Mar 2016
Modifié(e) : Star Strider le 1 Avr 2016
You’re asking for column 59 of a 58-column matrix.
Think about it ...
EDIT Seeing only the part of your code that you posted (about 8 hours ago), I would simply reverse the values of ‘m2’ and ‘n2’ in your loops.
  2 commentaires
Serena Woolridge
Serena Woolridge le 4 Avr 2016
Thanks, i have tried reversing the values but i get the same error. Is ther any other way to clear this?..
Star Strider
Star Strider le 4 Avr 2016
In these lines:
m2 = m1*ms;
n2 = n1*ms;
the ‘ms’ variable has to be greater than 0 and less than or equal to 1 for that to work correctly.
The only way I can come up with to avoid addressing outside the dimensions of your image is with something like this:
m2 = fix(max(1,m2));
m2 = fix(min(m1,m2));
n2 = fix(max(1,n2));
n2 = fix(min(n1,n2));
That limits the index variables to the limits of your image size.

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Plus de réponses (2)

MHN
MHN le 31 Mar 2016
So, you should not attempt to get b(1,59) when the size of b is (93,58) !!!

Walter Roberson
Walter Roberson le 1 Avr 2016
Consider the possibility that you have m2 and n2 exchanged in your code.
Another possibility: did you use
[m2, n2] = size(YourMatrix)
and your image is a color image? If so then you have a bug because of the way that size() is defined when you have fewer outputs than the array has dimensions. Instead use
[m2, n2, ~] = size(YourMatrix)
  2 commentaires
Serena Woolridge
Serena Woolridge le 4 Avr 2016
Thanks, i have tried both the alternatives provided by you but the same error keeps appearing. Is there any other method that can be done to clear this error?? thanks in advance.
Walter Roberson
Walter Roberson le 4 Avr 2016
We need to see your code.

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