Break a big matrix into cell array based on repetitive number in one of the matrix columns

I have a matrix of 383533*3 doubles, column 2 includes some repetitive numbers, like 2.5483e+06 here, which is similar for 600 raw. how I can break down this big matrix into cells which each cell includes 3 columns of numbers which second column is constant for each cell.

Answer 1

[Star Strider]

This approach works:

M = randi(9, 20, 3);                                % Create Data
M(1:9,2) = ones(9,1)*3;                             % Create Data
M(10:end,2) = ones(11,1)*7;                         % Create Data

[U2,ia,ic] = unique(M(:,2));                        % Unique Values In Column #2
rows = accumarray(ic, 1);                           % Lengths Uf Unique Values
Result = mat2cell(M, rows, size(M,2));              % Cell Array Of Separated Matrices

[Mori]

nice thanks.

[Star Strider]

Thank you. My pleasure!

Answer 2

[Azzi Abdelmalek]

%------Example---------------
A(1:1000,[1 3])=randi(100,1000,2)
A(:,2)=randi(3,1000,1)
%-----The code-----------------
[ii,jj,kk]=unique(A(:,2))
out=accumarray(kk,(1:numel(kk))',[],@(x) {A(x,:)})

[Mori]

Thanks Azzi, that works too