regexp string to numeric array

I have what seems like a common problem: a series of strings containing numeric data mixed with text. I want to extract those numbers into vectors or arrays. I have come up with the mock-up below, but it feels like a cludge. Is there a simple, readable one-liner that does the same?

    str = {'bob22alice666buster2', 'donald42lisa00buddy9'};
    pat = '\w*(\d{2})\w*(\d{2,3})\w*(\d{1})';
    for idx = 1:2
        tmp = regexp(str{idx}, pat, 'tokens');
        male(idx)   = str2double(tmp{1}(1));
        female(idx) = str2double(tmp{1}(2));
        doggie(idx) = str2double(tmp{1}(3));
    end

I was hoping for something ala:

for ...
  Mx3arr = str2num(regexp(str{idx}, pat, 'tokens')');
end

Answer 1

[Jan]

    str = {'bob22alice666buster2', 'donald42lisa00buddy9'};
    pat = '\w*(\d{2})\w*(\d{2,3})\w*(\d{1})';
    tmp = regexp(str, pat, 'tokens');
    C1  = cat(1, tmp{:});
    C2  = cat(1, C1{:});
    M   = str2double(C2);

I still prefer the dull string parsing without regexp:

S = sprintf('%s ', str{:});
S(isstrprop(S, 'alpha')) = ' ';
M = sscanf(S, '%d', [3, inf]);

Although it looks less smart, it works without clutter and much faster.

Answer 2

[Stephen23]

Assuming that every string contains exactly the same number of numeric data:

str = {'bob22alice666buster2', 'donald42lisa00buddy9'};
tmp = regexp(str,'\d+','match');
mat = str2double(vertcat(tmp{:}))

mat = 2×3

22 666 2 42 0 9