Dealing with NaNs in a code
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Hi everyone, I'm struggling with a code that doesn't accept the NaNs. This is a part of a bigger code:
data = [y1 y2];
for i=1:5
c(:,i) = mean(data(:,i));
d(:,i)=(data(:,i));
data_demeaned(:,i) = d(:,i) - c(:,i);
end
I've tried to do this:
c(:,i) = nanmean(data(:,i));
d(:,i)= data(:,i)(~isnan(data(:,i)));/ d(:,i)=~isnan(data(:,i));
data_demeaned(:,i) = d(:,i) - c(:,i);
but it doesn't work. Any suggestion would be highly appreciated.
Réponses (1)
Star Strider
le 7 Avr 2017
I believe you’re making this more difficult than it needs to be. I do not understand what you are doing with your ‘d’ matrix, since the code doesn’t make sense, so please explain it.
Try this:
data = rand(1,30); % Create Data
data(randperm(30,10)) = NaN; % Create Data (Insert ‘NaN’ Values)
data = reshape(data, [], 5); % Create Data
c = nanmean(data);
data_demeaned = data - c;
12 commentaires
Nicu Sprincean
le 7 Avr 2017
Modifié(e) : Nicu Sprincean
le 7 Avr 2017
Star Strider
le 7 Avr 2017
I don’t know what you’re doing, so I don’t know if interpolating the NaN values to eliminate the missing values are acceptable options. If they are, John D’Errico’s inpaint_nans (link) or related functions would be the way to go.
Nicu Sprincean
le 7 Avr 2017
Modifié(e) : Nicu Sprincean
le 7 Avr 2017
Star Strider
le 7 Avr 2017
Please see my previous Comment.
I still don’t know what you’re doing, what ‘call_fct’ is or does, or whether interpolating the NaN values are appropriate.
Nicu Sprincean
le 7 Avr 2017
Modifié(e) : Nicu Sprincean
le 7 Avr 2017
Star Strider
le 7 Avr 2017
I’m still lost as to what you’re doing.
If you want to eliminate the rows with NaN values from all your data, create a logical vector, then apply it to every row of every subset of your data:
Example —
data = rand(1,50); % Create Data
data(randperm(50,5)) = NaN; % Create Data (Insert ‘NaN’ Values)
data = reshape(data, [], 5); % Create Data (Matrix)
Lidx = ~any(isnan(data),2); % Logical Index: ‘0’ If ‘any’ Element In A Row Is ‘NaN’
Then use ‘Lidx’ as the row index in your data.
Nicu Sprincean
le 8 Avr 2017
Modifié(e) : Nicu Sprincean
le 8 Avr 2017
Star Strider
le 8 Avr 2017
Nicu Sprincean
le 8 Avr 2017
Modifié(e) : Nicu Sprincean
le 8 Avr 2017
Star Strider
le 8 Avr 2017
My pleasure.
The MATLAB cov code is likely optimized to be efficient. Please read and understand the documentation I linked to, in order to understand how to apply the various ‘nanflag’ options to your problem. One of them should work with your data.
Nicu Sprincean
le 10 Avr 2017
Modifié(e) : Nicu Sprincean
le 10 Avr 2017
Star Strider
le 10 Avr 2017
My pleasure.
That is normal, and results from numeric arrays not being defined to have ‘empty’ elements, so the matrix structure disappears and produces a vector of the ‘non-NaN’ values. (Cell arrays can have empty elements.)
You can create the original matrix as a cell array with the num2cell function. That will allow ‘empty’ elements, although it introduces the complexities of calculating with cell arrays, and does not eliminate your original problem.
That it has (Mx1) elements indicates to me that it has (M-1)*N elements that were NaN.
Since you have functions available that automatically calculate with NaN values and handle them as you want them to, I would just use those functions and not deal with eliminating the NaN values or using cell arrays.
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