Skipping fzero error in a loop

2 vues (au cours des 30 derniers jours)
Saeid
Saeid le 14 Avr 2017
I am trying to solve an algabraic equation with two parameters that are varying in a loop. The basic form of the program is as follows:
nn=linspace(0.01,1,10);
aa=logspace(0,3,10);
inn=length(nn);
iaa=length(aa);
ss=1+1./nn;
for ii=1:inn
for jj=1:iaa
ii
jj
Y0=[0 1];
fun=@(Y) (1+Y)^ss(ii)-Y^ss(ii)-ss(ii)*aa(jj);
YY(ii,jj)=fzero(fun,Y0)
end
end
Now at some point at values of ii=2 & jj=7 the programs figures that a solution is not available, and stops. The error message reads: "The function values at the interval endpoints must differ in sign.", which understandably is due to the nature of the
Is there a way to get the program to keep running?

Réponse acceptée

Star Strider
Star Strider le 14 Avr 2017
Yes!
Now I suppose you want to know how?
Define: ‘Y0=1’, not a vector of values. This gives you a matrix with many NaN values and many others with solutions outside ‘[0 1]’. You can convert these to NaN on your own later if you like, with:
YY(YY>1) = NaN;
The point is that the code completes and fills your matrix.

Plus de réponses (1)

the cyclist
the cyclist le 14 Avr 2017
One possible solution is to use a try-catch control structure.

Catégories

En savoir plus sur Dynamic System Models dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by