How can i position the minimum value in the first cell for each column, without changing the sequence?
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Utsav Vishal
le 20 Avr 2017
Commenté : Utsav Vishal
le 20 Avr 2017
I have a 100 x 1000 array, with the minimum value at the different position for each column. How can I position the minimum value in the first cell for each column, without changing the sequence?
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Star Strider
le 20 Avr 2017
This should do what you want:
M = randi(9,6,4); % Create Matrix
for k1 = 1:size(M,2)
[~,idx] = min(M(:,k1)); % Index Of Minimum In Column ‘k1’
Mr(:,k1) = circshift(M(:,k1), 1-idx, 1); % Rotate To Put First Minimum In First Row
end
M =
1 6 9 5
6 4 3 3
9 5 7 4
3 9 3 2
1 4 9 4
4 7 3 4
Mr =
1 4 3 2
6 5 7 4
9 9 3 4
3 4 9 5
1 7 3 3
4 6 9 4
Here ‘M’ is the original matrix, ‘Mr’ is the ‘rotated’ matrix. The circshift function will do what you want.
Note that the min (and max) functions only return the index of the first value of the minimum in a vector, if there are duplicates.
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Roger Stafford
le 20 Avr 2017
[~,I] = min(A,[],1);
for k = 1:size(A,2);
A(:,k) = circshift(A(:,k),1-I(k),1);
end
5 commentaires
Roger Stafford
le 20 Avr 2017
Given the error you received, try this instead:
[~,I] = min(A,[],1);
for k = 1:size(A,2);
A(:,k) = circshift(A(:,k),1-I(k));
end
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