Varargin - mistake in my example
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Gennaro Arguzzi
le 13 Mai 2017
Réponse apportée : Andrei Bobrov
le 13 Mai 2017
Hi everyone, I wrote the following function:
function [x] = ingressi_arbitrari(varargin)
x=0;
for k=1:nargin
x=x+1;
end
end
Why if I run a=ingressi_arbitrari([2 3]) in the command window, the result is a=1 instead of a=2 (I choose two input arguments)?
Thank you very much.
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Walter Roberson
le 13 Mai 2017
You only have one input argument, that happens to be length 2. If you had
a=ingressi_arbitrari([2 3], [7; 1; 8; 5])
then you would have two input arguments, the first length 2 and the second length 4
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