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How to display images from a cell array?

9 vues (au cours des 30 derniers jours)
fiona rozario
fiona rozario le 31 Mai 2017
Commenté : Image Analyst le 1 Juin 2017
I have 5 images in a cell array 'imageshares' and I want to display them individually.
figure
image(imageshares{i}));
I used the above code and obviously this didn't work. How do I display the images?
  4 commentaires
Matthew Eicholtz
Matthew Eicholtz le 31 Mai 2017
It would be helpful to see more of your code so we can properly diagnose the problem.
fiona rozario
fiona rozario le 1 Juin 2017
f=imread('test2.jpg');
red=f(:,:,1);
green=f(:,:,2);
blue=f(:,:,3);
[r,c,d]=size(f);
shred=zeros(r,c);
shgreen=zeros(r,c);
shblue=zeros(r,c);
image=zeros(r,c);
N = input('Number of pieces to break into ');
rowgroups = diff( round(linspace(0,r,N+1)));
rshares = mat2cell(red, rowgroups, size(red,2));
gshares = mat2cell(green, rowgroups, size(green,2));
bshares = mat2cell(blue, rowgroups, size(blue,2));
imageshares=mat2cell(image, rowgroups, size(image,2));
shredshares = mat2cell(shred, rowgroups, size(shred,2));
shgreenshares = mat2cell(shgreen, rowgroups, size(shgreen,2));
shblueshares = mat2cell(shblue, rowgroups, size(shblue,2));
for i=1:N
imageshares{i}=cat(3,rshares{i},gshares{i},bshares{i});
figure
image(imageshares{i});
end

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Réponses (2)

Star Strider
Star Strider le 31 Mai 2017
The subscript error is puzzling if ‘i=1:N’. One option is to change the loop counter variable to ‘k’ instead, since a few versions back, ‘i’ could default to the imaginary operator.
The imshow function could be a preferable option (with the index variable change):
figure
imshow(imageshares{k})
This is a guess on my part. If I guessed wrong, I will delete this Answer.
  1 commentaire
fiona rozario
fiona rozario le 1 Juin 2017
I tried this but still got the same error.

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Image Analyst
Image Analyst le 1 Juin 2017
image is a built in function. Thus, this makes no sense:
imageshares=mat2cell(image, rowgroups, size(image,2));
and I don't know what you're doing with all that "shares" stuff. You read in one image, which has 3 color channels, so exactly what 5 images are you expecting to see?
  2 commentaires
fiona rozario
fiona rozario le 1 Juin 2017
I entered the value of N as 5, which is the number of parts the matrix needs to be divided into. I need to divide the RGB components into parts or shares and then combine the individual components to form 5 images.
I changed the 'image' variable name and still got the same error.
Image Analyst
Image Analyst le 1 Juin 2017
To split up an image into tiles: see the FAQ

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