How do I convert to nan all entries with a particular value in a cell array?
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Each entry of the cell array is a matrix, and I want to convert to nan all entries, say, of value=1. Something like this: a=cellfun(@(x) x(x==1)=nan, a, 'un',0)
I tried to do this by creating a separate function, but I need to delete different values from the matrix assigned to each cell in the cell array, so I'm not sure how that would work. Can I just define a cell function like this?
function out = replaceval(in, val)
in(in==val) = NaN;
out = in;
end
1 commentaire
Rik
le 14 Juin 2017
This should work as far as I can tell. Keep in mind that you might have to replicate your second input as a cell if it is not the same for the cell you are using as first input.
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Star Strider
le 14 Juin 2017
I could not get this to work with only cellfun calls, and needed to use a loop.
This works:
C = {randi(9,5), randi(9,5), randi(9, 5)}; % Create Data
L = cellfun(@(x) x == 1, C, 'Uni',0); % Logical Arrays
C1 = C{1} % Display Initial Values
L1 = L{1} % Display Logical Arrays
for k1 = 1:size(C,2)
C{k1}(L{k1}) = NaN; % Replace With ‘NaN’
end
New_C1 = C{1} % Display Replaced Values
C1 =
2 4 9 3 5
1 8 1 3 7
4 5 2 3 4
5 3 7 6 1
6 5 7 6 8
L1 =
5×5 logical array
0 0 0 0 0
1 0 1 0 0
0 0 0 0 0
0 0 0 0 1
0 0 0 0 0
New_C1 =
2 4 9 3 5
NaN 8 NaN 3 7
4 5 2 3 4
5 3 7 6 NaN
6 5 7 6 8
Remove the ‘Display’ lines. They exist only to demonstrate the results.
2 commentaires
Star Strider
le 15 Juin 2017
In my code, the logical cell arrays ‘L’ will by definition have the same dimensions as the matrices they are derived from. That is the advantage of calculating them in a separate step.
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