Effacer les filtres
Effacer les filtres

how can i solve problem in my code for adaptive median filter

5 vues (au cours des 30 derniers jours)
Daleel Ahmed
Daleel Ahmed le 28 Oct 2017
function f= dd(r,Smax)
if (Smax <= 1) | (Smax/2 == round(Smax/2)) | (Smax ~= round(Smax))
error('SMAX must be an odd integer > 1.')
end
[M, N] = size(r);
% Initial setup.
f = r;
f(:) = 0;
alreadyProcessed = false(size(r));
%Begin filtering.
for k = 3:2:Smax
zmin = ordfilt2(r, 1, ones(k, k), 'symmetric');
zmax = ordfilt2(r, k * k, ones(k, k), 'symmetric');
zmed = medfilt2(r, [k k], 'symmetric');
processUsingLevelB = (zmed > zmin) & (zmax > zmed) & ...
~alreadyProcessed;
zB = (r > zmin) & (zmax > r);
outputZxy = processUsingLevelB & zB;
outputZmed = processUsingLevelB & ~zB;
f(outputZxy) = r(outputZxy);
f(outputZmed) = zmed(outputZmed);
alreadyProcessed = alreadyProcessed | processUsingLevelB;
if all(alreadyProcessed(:))
break;
end
end
% Output zmed for any remaining unprocessed pixels. Note that this
% zmed was computed using a window of size Smax-by-Smax, which is
% the final value of k in the loop.
f(~alreadyProcessed) = zmed(~alreadyProcessed);
  1 commentaire
Daleel Ahmed
Daleel Ahmed le 28 Oct 2017
Modifié(e) : Walter Roberson le 28 Oct 2017
Error using ordfilt2
Expected input number 1, A, to be one of these types:
double, single, uint8, uint16, uint32, uint64, int8, int16, int32, int64, logical
Instead its type was char.

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Walter Roberson
Walter Roberson le 28 Oct 2017
You appear to be attempting to pass in characters for the first input to your function, the one named "r" here. That input must be numeric for this code to work.

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Zeeshan Salam
Zeeshan Salam le 24 Mar 2019
can u send me working of this algorithm and flowchart

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