17 views (last 30 days)

Hi, I would like to ask how I could sum over a n dimensional matrix except one dimension, so the output is a vector. The ndims are not known in forehand. The summation is giving always a vector. (In my case a marginal pdf in statistics). Something like sum(K(:) except i-th dimension)

The best in a cyclus ( ndims not known).

For example having matrix K, the sums would be [6 22], [12 16], [10 18]

K(:,:,1) =

0 1

2 3

K(:,:,2) =

4 5

6 7

Stephen Cobeldick
on 2 Nov 2017

Edited: Stephen Cobeldick
on 2 Nov 2017

Here is one very simple way:

>> d = 3; % dimension

>> v = 1:ndims(K);

>> v([1,d]) = v([d,1]);

>> s = sum(reshape(permute(K,v),size(K,d),[]),2)

s =

6

22

It works by swapping the first and the desired dimension, then reshaping so that all trailing dimensions are reduced to one. The sum is then trivially along each row.

Note that the method I show here also has the significant advantage that it does not create any variables with copies of the data from the input array: this will be important for scaling to larger input arrays. Also note that slow and complex arrayfun or cellfun are not required for this task!

Stephen Cobeldick
on 2 Nov 2017

Just change the dimension d. It is on the very first line of code, I even labeled it for you.

" It gives [6 22]. "

No, it gives all of the answers that you showed in your question. How do I know this? Because I tested it. You just need to change the dimension value d. It would be trivial to do this in a loop, if you need to.

Stephen Cobeldick
on 2 Nov 2017

@Rafael Schwarzenegger: the dimensions of the input array are automatically measured using ndims(K).

Cedric Wannaz
on 2 Nov 2017

Here is one way, but there is probably a simpler approach:

buffer = arrayfun(@(k) permute(KL, circshift(1:ndims(KL), k-1)), 1:ndims(KL), 'UniformOutput', false) ;

s = cellfun(@(M) sum(reshape(M, [], size(M,2))), buffer, 'UniformOutput', false) ;

where s is a cell array of sum vectors.

EDIT : I won't have time, but maybe you can see how dimensions work with SHIFTDIM and understand how to have the outputs ordered as needed:

buffer = arrayfun(@(k) shiftdim(KL, k-1), 1:ndims(KL), 'UniformOutput', false) ;

s = cellfun(@(M) sum(reshape(M, [], size(M,2))), buffer, 'UniformOutput', false) ;

PS : you'll have to test whether it really does what you need. The approach is based on the fact that MATLAB reads memory column first

Stephen Cobeldick
on 2 Nov 2017

@Rafael Schwarzenegger: See my answer for a simpler, neater, and much more efficient solution.

Cedric Wannaz
on 2 Nov 2017

Opportunities for recent engineering grads.

Apply TodayFind the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!
## 3 Comments

## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500128

⋮## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500128

## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500135

⋮## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500135

## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500168

⋮## Direct link to this comment

https://fr.mathworks.com/matlabcentral/answers/364673-sum-of-matrix-omitting-one-dimension#comment_500168

Sign in to comment.