Why cannot I plot my pressure to my volume?

Hello, I do have two tables (both 5001x1) One represents the pressure and one represents volume. Now I want to plot these. When I select both I cannot use the plots in the upper menu. When using it in the command windows

plot(pressure,volume)

gives me the error:

Too many arguments

What am I doing wrong here?

Thanks in advance

Answer 1

[Walter Roberson]

? You cannot pass table objects themselves to plot(); plot() is not defined on table objects.

But that would give you a different error. More likely you should check with

which -all plot

as you probably somehow have a different plot.m on your path.

[Christian Berwanger]

which -all plot shows me just some matlab paths. None of these is an own function or variable.

Answer 2

[Star Strider]

You most likely have a variable named ‘plot’.

Run this from a script or your Command Window:

which plot -all

If the first line is:

plot is a variable.

you have found the problem. (This is called ‘overshadowing’ a function.) The solution is to rename the variable to something that does not conflict with a function name.

[Christian Berwanger]

This isn't the problem. which plot -all just shows me some matlab paths

[Star Strider]

You mentioned that your variables are ‘tables’. What are their exact data class?

You can determine this from:

class(pressure)
class(volume)

[Christian Berwanger]

I get both times

ans = 
  'table'

[Star Strider]

You will need use the table2array function to convert them to double arrays, then plot them.

[Walter Roberson]

Or use

plot( pressure{:,1}, volume{:,1} )