Please help with Index exceeds matrix dimensions error

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Christopher Carey
Christopher Carey le 3 Déc 2017
Commenté : Star Strider le 3 Déc 2017
%%here is my code
clc; close all;
N=50;
x = zeros(1,N);
for n = 1:length(x)
x(n)= sin((n/16)*pi);
end
y= zeros(1,N);
y(1)=-0.13;
for n = 2:length(x)
y(n+1)=(-1/3)*x(n+2)+(1/2)*x(n+1)+(1/3)*x(n)+y(n);
end
stem(0:1:50, y, 'r-');
xlabel('n');
ylabel('y[n]');
title('Output y[n] of the system');
pause;

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Star Strider
Star Strider le 3 Déc 2017
This will eliminate the error:
for n = 2:length(x)-2
y(n+1)=(-1/3)*x(n+2)+(1/2)*x(n+1)+(1/3)*x(n)+y(n);
end
however you have to change the stem arguments accordingly:
stem(0:1:49, y, 'r-')
  2 commentaires
Christopher Carey
Christopher Carey le 3 Déc 2017
thank you very much would you mind explaining how this fixes it please, I am a beginner at MATLAB.
Star Strider
Star Strider le 3 Déc 2017
As always, my pleasure.
You are indexing x(n+2) in your code, and ‘x’ has only 50 elements. In order to avoid reading beyond the number of elements in ‘x’, you need to reduce the number of iterations by 2. Setting the iterations to 2:length(x)-2 accomplishes that, since ‘n’ now goes from 2 to 48.

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