How to plot the best fit when x-axis has only one value?

5 vues (au cours des 30 derniers jours)
Safi ullah
Safi ullah le 10 Jan 2018
Commenté : Star Strider le 10 Jan 2018
Hi everyone, my data and code is given below,
x1 = [9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,];
x2= [39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27];
y1=[2.49849031538000e-15,2.49502658466163e-15,2.49502495000000e-15,2.50264303379900e-15,2.49502658466163e-15,2.49502495000000e-15,2.49560122336855e-15,8.17662331186994e-16,6.29990432061625e-16,2.12956584547500e-15,1.91935478762000e-15,2.63195081946000e-15,3.12979948175000e-15,3.09444418405000e-15,3.09233615855000e-15,3.01050170545000e-15,3.06054718890000e-15,3.11567416400000e-15,3.13276918045000e-15,3.05145014445000e-15,2.99728379425000e-15,3.12172508790000e-15,2.56985506485000e-15,3.20864482505000e-15,2.97324731355000e-15,2.56209731145000e-15,1.64972623540000e-15,1.62535722858500e-15,1.54636514685000e-15,1.28859402225000e-15,1.46049846936000e-15,1.33810415355000e-15,1.14215819083000e-15,8.42920403255000e-16];
y2=[1.50485306240000e-18,1.50775125440000e-18,1.34939445270000e-18,1.46522490255000e-18,1.29700159840000e-18,1.07510058980000e-18,1.18186725355000e-18,6.96921304120000e-18,1.10896235555000e-18,1.88431177410000e-18,2.06954144735000e-18,3.69742782500000e-18,4.50267051220000e-18,5.18527090055000e-18,4.27703042175000e-18,4.08381752195000e-18,4.36270874670000e-18,3.90556129885000e-18,3.54560734945000e-18,2.57385028340000e-18,2.66198817935000e-18,3.65437028765000e-18,2.19580890635000e-18,2.08296552040000e-18,1.69517276020000e-18,1.56244075620000e-18,1.34416563130000e-18,1.63989745735000e-18,1.61394252125000e-18,1.55418026030000e-18,1.42952255035000e-18,1.29278442465000e-18,1.16687040735000e-18,1.29804106530000e-18];
loglog(x1,y1,'*b')
hold on
loglog(x2,y2,'*r')
I need the first order best fit of this data and code,thanks.
  3 commentaires
the cyclist
the cyclist le 10 Jan 2018
It's not very clear what your goal is for this "fit". Do you want to predict or simulate values for x1 and x2 separately?
Are your trying to predict y values for values of x that are different from your x1 and x2? (That seems like a fool's errand.)
You need to tell us more about what you are planning to do with this fit.
Safi ullah
Safi ullah le 10 Jan 2018
I need to find best fit line between the red and blue points

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Réponse acceptée

Star Strider
Star Strider le 10 Jan 2018
Try this:
x1 = [9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,9.384,];
x2= [39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27,39.27];
y1=[2.49849031538000e-15,2.49502658466163e-15,2.49502495000000e-15,2.50264303379900e-15,2.49502658466163e-15,2.49502495000000e-15,2.49560122336855e-15,8.17662331186994e-16,6.29990432061625e-16,2.12956584547500e-15,1.91935478762000e-15,2.63195081946000e-15,3.12979948175000e-15,3.09444418405000e-15,3.09233615855000e-15,3.01050170545000e-15,3.06054718890000e-15,3.11567416400000e-15,3.13276918045000e-15,3.05145014445000e-15,2.99728379425000e-15,3.12172508790000e-15,2.56985506485000e-15,3.20864482505000e-15,2.97324731355000e-15,2.56209731145000e-15,1.64972623540000e-15,1.62535722858500e-15,1.54636514685000e-15,1.28859402225000e-15,1.46049846936000e-15,1.33810415355000e-15,1.14215819083000e-15,8.42920403255000e-16];
y2=[1.50485306240000e-18,1.50775125440000e-18,1.34939445270000e-18,1.46522490255000e-18,1.29700159840000e-18,1.07510058980000e-18,1.18186725355000e-18,6.96921304120000e-18,1.10896235555000e-18,1.88431177410000e-18,2.06954144735000e-18,3.69742782500000e-18,4.50267051220000e-18,5.18527090055000e-18,4.27703042175000e-18,4.08381752195000e-18,4.36270874670000e-18,3.90556129885000e-18,3.54560734945000e-18,2.57385028340000e-18,2.66198817935000e-18,3.65437028765000e-18,2.19580890635000e-18,2.08296552040000e-18,1.69517276020000e-18,1.56244075620000e-18,1.34416563130000e-18,1.63989745735000e-18,1.61394252125000e-18,1.55418026030000e-18,1.42952255035000e-18,1.29278442465000e-18,1.16687040735000e-18,1.29804106530000e-18];
xv = reshape([x1; x2], [], 1); % Create X-Vector
YM = reshape([y1; y2], [], 1); % Create Y-Vector
DM = [xv(:) ones(size(xv(:)))]; % Design Matrix
B = DM \ YM; % Estimate Parameters
YFit = DM * B; % Fit Regression For Plot
YFit = reshape(YFit, 2, [])';
figure(1)
loglog(x1,y1,'*b')
hold on
loglog(x2,y2,'*r')
plot([x1(1) x2(1)], YFit(1,:), '-pg')
hold off
  2 commentaires
Safi ullah
Safi ullah le 10 Jan 2018
@ Star Strider thanks your code work well.
Star Strider
Star Strider le 10 Jan 2018
As always, my pleasure.

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