How can I modify the code below to build a hexagon knowing the coordinates of the hexagon roofs?

Function []=polygon (sides)
sides=6;
radians=(2*pi)./sides;
r=ones(1,sides);
theta=1:radians:2*pi;
polar(theta,r)
end

I need to show the hexagon in the coordinate plane.The coordinates of each point should be the radius and angle from a specific point.

Answer 1

[Star Strider]

Try this:

function xy = polygon(sides)
radians=(2*pi)./sides;
r=ones(1,sides+1);
theta=0:radians:2*pi;
xy = [r(:).*cos(theta(:))  r(:).*sin(theta(:))];
end

then:

sides=6;
XY = polygon(sides)                                 % Call ‘polygon’ Function

figure
plot(XY(:,1),  XY(:,2))
axis([-1.1  1.1    -1.1  1.1])
axis equal

For best results, save the function to its own file as: polygon.m

[Jenny]

It still doesn't show any figure of the hexagon.

[Star Strider]

It plots a hexagon for me:

[Star Strider]

Jenny’s ‘Answer’ moved here:

It is strange. Can you send me please a picture of the code to see how you have written it in your PC? I am looking forward to see the hexagon but it doesn't appear. :) Maybe I have made any mistake..

[Star Strider]

I already posted all the code I used to create and plot the hexagon.

First, save the function to your MATLAB user path as polygon.m.

Second, run it from a script file with this code:

sides=6;
XY = polygon(sides)                                 % Call ‘polygon’ Function

figure
plot(XY(:,1),  XY(:,2))
axis([-1.1  1.1    -1.1  1.1])
axis equal

The plot should appear.

[Jenny]

Ok. I will try again. Thank you very much.

[Star Strider]

My pleasure.