index exceeds matrix dimensions

I'm having an issue with the following code that models token ring behaviour:
clc
clear all
syms k C W
E(C) = ((50*2.15e-4)/(1-(50*k*2.215e-4)));
E(W) = (((2.637e-8)*(1-0.02215*k + (1.227e-4)*k^2) - (1.15e-4)*(1-0.011075*k))/ (0.0215*(1-0.02215*k + (1.227e-4)*k^2) - (((2.31125e-4)*k)*(1-0.011075*k))));
hold all
fplot(((50*2.15e-4)/(1-(50*k*2.215e-4))))
xlabel('lamda');
ylabel('E(C)');
title('Graph of E(C) against Lamda','FontSize',12);
when this program runs the error 'index exceeds matrix dimensions' appears and states a problem with the line beginning flpot. anyone know how to fix this?

1 commentaire

John BG
John BG le 15 Jan 2018
Hi Nick
What version of MATLAB are you using?
With latest release your code works ok:

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Réponses (2)

Star Strider
Star Strider le 14 Jan 2018

0 votes

The fplot function is expecting a function and a range for the independent variable.
Try this:
fplot(@(k) ((50*2.15e-4)./(1-(50*k*2.215e-4))), [-1 1])

2 commentaires

Nick
Nick le 14 Jan 2018
works! thank you
Star Strider
Star Strider le 14 Jan 2018
My pleasure!
If my Answer helped you solve your problem, please Accept it!

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Walter Roberson
Walter Roberson le 14 Jan 2018

0 votes

The code runs to completion on newer versions of MATLAB. A couple of releases ago, fplot was improved to support symbolic expressions.
However, note that when you define
E(C) = expression1;
E(W) = expression2;
then you are overwriting E with the second statement. The statements are equivalent to
E = symfun(expression1, C);
E = symfun(expression2, W);
The syntax does not define two different functions, E subscript C and E subscript W.
Your fplot does not use either one at the moment though.

Question posée :

le 14 Jan 2018

Commenté :

le 15 Jan 2018

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