index exceeds matrix dimensions
Afficher commentaires plus anciens
I'm having an issue with the following code that models token ring behaviour:
clc
clear all
syms k C W
E(C) = ((50*2.15e-4)/(1-(50*k*2.215e-4)));
E(W) = (((2.637e-8)*(1-0.02215*k + (1.227e-4)*k^2) - (1.15e-4)*(1-0.011075*k))/ (0.0215*(1-0.02215*k + (1.227e-4)*k^2) - (((2.31125e-4)*k)*(1-0.011075*k))));
hold all
fplot(((50*2.15e-4)/(1-(50*k*2.215e-4))))
xlabel('lamda');
ylabel('E(C)');
title('Graph of E(C) against Lamda','FontSize',12);
when this program runs the error 'index exceeds matrix dimensions' appears and states a problem with the line beginning flpot. anyone know how to fix this?
1 commentaire
John BG
le 15 Jan 2018
Hi Nick
What version of MATLAB are you using?
With latest release your code works ok:

Réponses (2)
Star Strider
le 14 Jan 2018
The fplot function is expecting a function and a range for the independent variable.
Try this:
fplot(@(k) ((50*2.15e-4)./(1-(50*k*2.215e-4))), [-1 1])
2 commentaires
Nick
le 14 Jan 2018
Star Strider
le 14 Jan 2018
My pleasure!
If my Answer helped you solve your problem, please Accept it!
Walter Roberson
le 14 Jan 2018
The code runs to completion on newer versions of MATLAB. A couple of releases ago, fplot was improved to support symbolic expressions.
However, note that when you define
E(C) = expression1;
E(W) = expression2;
then you are overwriting E with the second statement. The statements are equivalent to
E = symfun(expression1, C);
E = symfun(expression2, W);
The syntax does not define two different functions, E subscript C and E subscript W.
Your fplot does not use either one at the moment though.
Catégories
En savoir plus sur Code Performance dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!