Hi guys,
I got 3 matrices that I want to concatenate into one. Each matrix is 4x200. What I want to do is to create a matrix that is like matrix c:
a =
8 1 6 5
3 5 7 6
4 9 2 7
b =
5 4 1 3
7 3 2 8
8 9 6 6
c = [a(:,1) b(:,1);a(:,2) b(:,2);a(:,3) b(:,3);a(:,4) b(:,4)]
c =
8 5
3 7
4 8
1 4
5 3
9 9
6 1
7 2
2 6
5 3
6 8
7 6
I want to use a for loop but I couldn't get it to work. Your help will be appreciated. Thank you!

3 commentaires

Catherine
Catherine le 21 Fév 2018
Modifié(e) : Catherine le 21 Fév 2018
I have tried:
t = 0;
g = 0;
for i = 1:size(a,2)
for j = 1:size(a,1)
c(t+1,g+1) = [a(j,i) b(j,i)];
t = t+1;
end
t = 0;
g = g+1;
end
g = 0;
But the error is dimension mismatch
per isakson
per isakson le 21 Fév 2018
Why for-loop?
Catherine
Catherine le 21 Fév 2018
I just thought it's the easiest way. If there is other ways, I am happy to try out as well. Thanks.

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 Réponse acceptée

Star Strider
Star Strider le 21 Fév 2018
Try this:
c = [a(:) b(:)];

4 commentaires

Catherine
Catherine le 21 Fév 2018
Modifié(e) : Catherine le 21 Fév 2018
Thanks! That's even easier.
As always, my pleasure!
Probably the easiest way is to create ‘v’ as a matrix, then concatenate it with the others:
v = repmat((1:size(a,1))', 1, size(a,2));
c = [v(:) a(:) b(:)];
Note the transpose operator ('). This creates ‘(1:size(a,1))’ as a column vector, necessary for the correct matrix creation.
This version of ‘v’ should work with any matrix ‘a’, since it is defined by the size dimensions of ‘a’.
Catherine
Catherine le 21 Fév 2018
Great! that works well! Thank you
Star Strider
Star Strider le 21 Fév 2018
As always, my pleasure!

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