Draw Triangle using quiver3 command in Matlab

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iam
iam le 28 Fév 2018
Commenté : Star Strider le 21 Mar 2018
Following are the position vectors that form vertices of a right angled triangle, a=[2 3 4], b=[6 2 -5], c=[8 1 -4]. I want to plot triangle using quiver3 command in Matlab. Any help will be appreciated. Thanks.

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Star Strider
Star Strider le 28 Fév 2018
Modifié(e) : Star Strider le 28 Fév 2018
Try this:
a=[2 3 4];
b=[6 2 -5];
c=[8 1 -4];
abc = [a; b; c; a];
dabc = diff([abc; a]);
figure(1)
plot3(abc(:,1), abc(:,2), abc(:,3), 'pg', 'MarkerSize',15, 'MArkerFaceColor','g')
hold on
quiver3(abc(:,1), abc(:,2), abc(:,3), dabc(:,1), dabc(:,2), dabc(:,3), 0, 'LineWidth',2)
hold off
grid on
xlabel('X')
ylabel('Y')
zlabel('Z')
view(150, 40)
Experiment to get the result you want. I do not know how well this will generalise to other shapes.
EDIT Improved efficiency of the ‘dabc’ calculation.
  6 commentaires
Gavin Seddon
Gavin Seddon le 21 Mar 2018
Hello Star strider how do I change the position of the arrowhead so it is at the hypotenuse terminus? Thank you. GS.
Star Strider
Star Strider le 21 Mar 2018
@Gavin Seddon — I do not understand what you are asking.
I encourage you to experiment with the code to get the result you want. In the second plot (link) the points are labeled, so you can follow them more easily.
The code with the labeled vertices is:
a=[2 3 4];
b=[6 2 -5];
c=[8 1 -4];
abc = [a; b; c; a];
dabc = diff([abc; a]);
figure(1)
plot3(abc(:,1), abc(:,2), abc(:,3), 'pg', 'MarkerSize',15, 'MarkerFaceColor','g')
hold on
quiver3(abc(:,1), abc(:,2), abc(:,3), dabc(:,1), dabc(:,2), dabc(:,3), 0, 'LineWidth',2)
hold off
grid on
axis([0 10 0 5 -6 5])
text(abc(1:end-1,1), abc(1:end-1,2), abc(1:end-1,3), {'\bfa\rm','\bfb\rm','\bfc\rm'}, 'HorizontalAlignment','center', 'VerticalAlignment','bottom', 'Color','r', 'FontSize',14)
xlabel('X')
ylabel('Y')
zlabel('Z')

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