ODE15s time vector size
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Lukasz Dziechciarczyk
le 15 Mar 2018
Réponse apportée : Lukasz Dziechciarczyk
le 15 Mar 2018
Hi everyone,
I am using an ode15s solver to solve some coupled equations and I put this into a for loop and for each iteration I solve the same equations but changing one parameter that goes into the equation (it's a constant). Now what I am seeing is that each time ode is giving me results, the time vector has a different size and I can't then put all of that into one matrix, since the resulting vectors are all different size. Is there a way around it? I am ok if the matrix would be of certain size to fit the longest time vector and the shorter vectors would have zeros added i.e.
So what I am doing:
for i=1:length(pump_barrel)
t_span = [0 3e-6]; % time-span
i_values = [0.9 0 0.1 0 0]; % initial values. [0 0 0] should be ok
tol = 0.0000000000001;
options = odeset('RelTol',tol,'AbsTol',[tol tol tol tol tol]);
[t,y] = ode15s(@(t,y) NV(t,y,argins),t_span,i_values,options); % calling the ode-solver
PL=y(:,2)+y(:,4);
disp(length(t))
PL_time(:,i)=y(:,2)+y(:,4); % here is a problem, first vector goes into the PL_time matrix, but the second is larger and throws error
end % end of the for loop in which I am changing a parameter in argins
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Jan
le 15 Mar 2018
Modifié(e) : Jan
le 15 Mar 2018
A tspan with 3 values has exactly the same physical meaning as with 2 values:
tspan1 = [t1, t3]
tspan2 = [t1, t2, t3]
For both tspan the integration runs from t1 to t3, but for tspan1 the trajectory is replied for each computed time step, where the step size controller determines the output times, while for tspan2 the trajectory is replied for exactly the times t1, t2, t3.
This is useful, if you need the trajectory to specific intermediate steps, e.g. for a fixed frame rate in a 3D animation.
For your problem, you can use:
tspan = linspace(0, 3e-6, 100);
to get the trajectory for 100 time points.
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Plus de réponses (2)
Torsten
le 15 Mar 2018
If t_span has more than two elements, the ode integrator will output the solution at exactly the specified time instants.
Best wishes
Torsten.
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Star Strider
le 15 Mar 2018
With more than two values, the ODE solvers will output its results at times closely corresponding to the times in the vector. For three values, it would output a three-row time vector (in your code, ‘t’), and a three-row vector or matrix of the ‘y’ values.
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