Why am I getting a parse error at the logical operator &&?

For some reason I am getting a parse error at && which will not allow my code to run.
function [nucleotides] = BMEactivity(m1, m2)
for i = 1:m1(end)
if m1(i) >= && m2(i) >= 0
nucleotides(i) = 'A';
elseif m1(i) < 0 && m2(i) >= 0
nucleotides(i) = 'C';
elseif m1(i) >= 0 && m2(i) < 0
nucleotides = 'G';
elseif m1(i) < 0 && m2(i) < 0
nucleotides(i) = 'T';
else
end
end
end
Also, I'm not quite sure if this is the correct syntax in the for loop for indexing to the last element of the array. It would be ideal if there was one expression that let me index to the end of m1 and m2 simultaneously.

 Réponse acceptée

You’re not incrementing the loop.
Try this:
m1 = randi([-1 1], 20, 1); % Create Data
m2 = randi([-1 1], 20, 1); % Create Data
for i = 1:numel(m1)
if m1(i) >= 0 && m2(i) >= 0
nucleotides(i) = 'A';
elseif m1(i) < 0 && m2(i) >= 0
nucleotides(i) = 'C';
elseif m1(i) >= 0 && m2(i) < 0
nucleotides(i) = 'G';
elseif m1(i) < 0 && m2(i) < 0
nucleotides(i) = 'T';
end
end

Plus de réponses (1)

In this line
if m1(i) >= (##) && m2(i) >= 0
You forget to write a number at (##).

4 commentaires

Ok so that was dumb and that part works now but now it is telling me that nucleotides isn't defined. for these inputs, I need it to be giving me the string 'CCGA' and I'm nit sure where I'm going wrong.
If you want your for loop to iterate through all the elements in m1, you don't want the upper limit to be m1(end). If m1(end) were less than 1, the body of your for loop wouldn't execute at all and so the nucleotides variable would indeed not be defined.
Use numel(m1) as the upper limit of your for loop instead. The numel function returns the NUMber of ELements in your array.
Ameer Hamza
Ameer Hamza le 3 Mai 2018
Modifié(e) : Steven Lord le 3 Mai 2018
Also, consider pre-allocation. For example before for loop, initialize nucleotides with zeros.
nucleotides = zeros(1, numel(m1));
[SL: fixed typo]
Thanks sm that helps!

Connectez-vous pour commenter.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by