counting the correct interval and stop at the end of it
2 vues (au cours des 30 derniers jours)
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Pd = 480; inter = 18; Cap = 200; hrs = 8640; initial = Cap; yyyy(1) = initial; yyy(1) = 0;
for e_ref = Pd:Pd:hrs for t=1:inter
if Pd(Pd >= 72 & Pd < 120)
yyy(t+1) = ((-0.00005667*e_ref(t) + 100)/100);
yyyy(t+1) = yyy(t+1)*Cap;
e_ref(t+1) = e_ref(t) + Pd;
elseif Pd == 480
yyy(t+1) = ((-0.00008999*e_ref(t) + 100)/100);
yyyy(t+1) = yyy(t+1)*Cap;
e_ref(t+1) = e_ref(t) + Pd;
end
end
end
1 commentaire
KALYAN ACHARJYA
le 21 Juil 2018
error in the code, pls provide the correct code, so that user help you easily.
Réponses (1)
KALYAN ACHARJYA
le 21 Juil 2018
%insert the following code within for loop, when Pd becomes 480, the loop execution stop
if Pd==480
return;
end
3 commentaires
KALYAN ACHARJYA
le 30 Juil 2018
Modifié(e) : KALYAN ACHARJYA
le 30 Juil 2018
OK, Unable to a response you on time.
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