another basic question for a beginner
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Eliraz Nahum
le 21 Sep 2018
Réponse apportée : Star Strider
le 21 Sep 2018
I saw the 2 forms of writing:
- fzero(f,x0)
- fsolve(@(x)f,xo)
in both cases we use symbolic function (f) before the above orders.
I am trying to understand why in the first case we could write only "f", while in the second one we had to write the whole expression "@(x)f"?
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Star Strider
le 21 Sep 2018
Without knowing the relevant context, it is difficult to say.
The first syntax:
fzero(f,x0)
implies that ‘f’ is a function of one variable, and already exists in the workspace as a function handle.
The second syntax:
fsolve(@(x)f,x0)
actually throws this error when I run it (in R2018b):
Error using fsolve (line 281)
FSOLVE requires all values returned by functions to be of data type double.
The correct way to use that syntax is to express ‘f’ as a function to be evaluated:
fsolve(@(x)f(x),x0)
and this works correctly.
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