Effacer les filtres
Effacer les filtres

How do I add values to a vector instead of replacing them?

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Skyer
Skyer le 19 Oct 2018
Commenté : Star Strider le 19 Oct 2018
Hey I'm trying to combine all IDs for pictures into a vector to use in a function but when I write this loop the values get replaced and i only get the value of the last i.
for i = 1:(length(p))
allIDs = [p(i) ImageIDs(1) ImageIDs(2) ImageIDs(3) ImageIDs(4)];
end
If I write "allIDs(i)" instead I get an error message saying they aren't compatible. How can I write this loop instead? Any help would be appreciated.

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Star Strider
Star Strider le 19 Oct 2018
Use a row and ‘default’ column subscript for allIDs:
allIDs(i,:) = [p(i) ImageIDs(1) ImageIDs(2) ImageIDs(3) ImageIDs(4)];
That should work.
  4 commentaires
Skyer
Skyer le 19 Oct 2018
Thank you! You've saved my friday evening.
Star Strider
Star Strider le 19 Oct 2018
As always, my pleasure!

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Plus de réponses (2)

YT
YT le 19 Oct 2018
I think you meant to do
allIDs(i,:)
  1 commentaire
Skyer
Skyer le 19 Oct 2018
Thanks for the answer, but I want them all to be on a single row in the new vector. Is this possible to do?

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Guillaume
Guillaume le 19 Oct 2018
All the answers assume you want to create a matrix, I'm not sure that's what you want since you mention a vector. In any case, I see nothing in the code given that warrants a loop, so allIDs as a matrix could be created in one fell swoop with:
allIDs = [p(:), repmat(ImageIDs(1:4), numel(p), 1)];
As said, I'm not convinced that's what's desired but if it's not a better explanation is required, in particular, an explanation of what p and ImageIDs are (size, type).
  1 commentaire
Skyer
Skyer le 19 Oct 2018
Thanks for the answer. I get an error message "Error using horzcat Dimensions of arrays being concatenated are not consistent." using this. Do you know what it means and how to fix it?

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