plotting matrix verses vector

Good evening

I want to plot a frequency vector (x-axes) with a path loss matrix which is 16*16

I tried this but it gives me an error

    figure(1);
                plot(p.f,H(1,:),
                     p.f,H(2,:),
                     p.f,H(3,:),
                     p.f,H(4,:),
                     p.f,H(5,:),
                     p.f,H(6,:),
                     p.f,H(7,:),
                     p.f,H(8,:),
                     p.f,H(9,:),
                     p.f,H(10,:),
                     p.f,H(11,:),
                     p.f,H(12,:),
                     p.f,H(13,:),
                     p.f,H(14,:),
                     p.f,H(15,:),
                     p.f,H(16,:));

[Steven Lord]

What is the full text (everything displayed in red) of the error message?

What do the following commands show?

sf = size(p.f)
cf = class(p.f)
sh = size(H)
ch = class(H)

[Stephen23]

You could just plot the whole matrix like this:

plot(p.f,H.')

[Alice Faisal]

Vectors must be the same length.

It gives me this error now

Answer 1

[Star Strider]

The easiest solution is likely:

plot(p.f, H)

If ‘H’ is a square matrix, and you want to transpose it, use:

plot(p.f, H.')

instead.

[Alice Faisal]

Vectors must be the same length.

It gives me this error now

[Star Strider]

I assumed ‘p.f’ is a vector.

If it a matrix the same size as ‘H’, either of my plot calls will work:

p.f = rand(16);
H = rand(16, 16);
figure
plot(p.f, H)

If not, you will have to choose what vector in ‘p.f’ to plot with. The vector must have 16 elements to plot with your (16x16) matrix.

Answer 2

[madhan ravi]

An example its possible using loop:

H=rand(16)
p.f = 1:16

figure(1);
 for i = 1:length(H)
                plot(p.f(1,:),H(i,:))
                hold on
 end