plotting matrix verses vector
6 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Good evening
I want to plot a frequency vector (x-axes) with a path loss matrix which is 16*16
I tried this but it gives me an error
figure(1);
plot(p.f,H(1,:),
p.f,H(2,:),
p.f,H(3,:),
p.f,H(4,:),
p.f,H(5,:),
p.f,H(6,:),
p.f,H(7,:),
p.f,H(8,:),
p.f,H(9,:),
p.f,H(10,:),
p.f,H(11,:),
p.f,H(12,:),
p.f,H(13,:),
p.f,H(14,:),
p.f,H(15,:),
p.f,H(16,:));
3 commentaires
Stephen23
le 26 Oct 2018
You could just plot the whole matrix like this:
plot(p.f,H.')
Réponses (2)
Star Strider
le 26 Oct 2018
The easiest solution is likely:
plot(p.f, H)
If ‘H’ is a square matrix, and you want to transpose it, use:
plot(p.f, H.')
instead.
2 commentaires
Star Strider
le 26 Oct 2018
I assumed ‘p.f’ is a vector.
If it a matrix the same size as ‘H’, either of my plot calls will work:
p.f = rand(16);
H = rand(16, 16);
figure
plot(p.f, H)
If not, you will have to choose what vector in ‘p.f’ to plot with. The vector must have 16 elements to plot with your (16x16) matrix.
madhan ravi
le 26 Oct 2018
Modifié(e) : madhan ravi
le 26 Oct 2018
An example its possible using loop:
H=rand(16)
p.f = 1:16
figure(1);
for i = 1:length(H)
plot(p.f(1,:),H(i,:))
hold on
end
0 commentaires
Voir également
Catégories
En savoir plus sur Annotations dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!