a=[2 3 2;3 3 3;4 4 4;2 5 4; 3 5 5; 4 4 4; 7 3 4]
how do I delete only those rows where elemets repeat for entire row length. In this example matrix, the three rows with all 3s and all 4s where this happens.

 Réponse acceptée

Star Strider
Star Strider le 25 Nov 2018
Try this:
a=[2 3 2;3 3 3;4 4 4;2 5 4; 3 5 5; 4 4 4; 7 3 4];
a_new = a(all(diff(a,[],2) ~= 0, 2),:)
If all the columns in a particular row are the same, the vector returned by the diff function will all be uniformly 0. The all function across rows (dimension = 2) detects that, and deletes those rows.
a =
2 3 2
3 3 3
4 4 4
2 5 4
3 5 5
4 4 4
7 3 4
a_new =
2 3 2
2 5 4
7 3 4

3 commentaires

klb
klb le 26 Nov 2018
i want only the row with all elements same to be eliminated. so n ,n, x >> keep but n, n ,n>> delete
klb
klb le 26 Nov 2018
ok i repalced 'all' with 'any' and that gives the requried answer. But thank you! Now on to researching the finess between all and any...
Star Strider
Star Strider le 26 Nov 2018
As always, my pleasure.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 25 Nov 2018

0 votes

mask = all(diff(a, [], 2) == 0)
Now you can use mask as the row selector in deletion.

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