How can plot multiple same amplitude signals along with same y axis ?

1 vue (au cours des 30 derniers jours)
Zara Khan
Zara Khan le 22 Jan 2019
Commenté : Star Strider le 2 Fév 2019
I am using this code to plot multiple signals. But unable to plot using same y axis. I am some overlapping plot due same amplitude. How to manage them in same figure? Signals will be in dufferent length but later I want to scale them with same length. I am attaching figure that is representing how will be my output.
clc;
close all;
clear;
workspace;
a = imread('img.png');
bwimg =bwareafilt(~a, 1);
s=regionprops(bwimg,'Orientation','Centroid','MajorAxisLength','MinorAxisLength');
circleCenterX =s.Centroid(1);
circleCenterY =s.Centroid(2);
diameters = mean([s.MajorAxisLength s.MinorAxisLength],2);
t=0:0.001:2*pi;
r1 =1*diameters/8;
x = circleCenterX + r1 * sin(t);
y = circleCenterY + r1 * cos(t);
[r,c]=size(bwimg);
bw=false(r,c);
t=0:0.001:2*pi;
bw =bw|poly2mask(x,y,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x1=thisBoundary(:,2);
y1=thisBoundary(:,1);
indexes = y1<circleCenterY; % Only those in the upper half.
xTop = x1(indexes);
yTop = y1(indexes);
figure;
for k=1:length(xTop )
profile(k) = bwimg(yTop(k),xTop(k ));
plot(profile,'r-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r2 =2*diameters/8;
x2 = circleCenterX + r2 * sin(t);
y2 = circleCenterY + r2 * cos(t);
bw =bw|poly2mask(x2,y2,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x3=thisBoundary(:,2);
y3=thisBoundary(:,1);
indexes = y3<circleCenterY; % Only those in the upper half.
xTop1 = x3(indexes);
yTop1= y3(indexes);
for k=1:length(xTop1)
profile1(k) = bwimg(yTop1(k),xTop1(k ));
plot(profile1,'b-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r3 =7*diameters/8;
x4= circleCenterX + r3 * sin(t);
y4= circleCenterY + r3 * cos(t);
bw =bw|poly2mask(x4,y4,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x5=thisBoundary(:,2);
y5=thisBoundary(:,1);
indexes = y5<circleCenterY; % Only those in the upper half.
xTop2 = x5(indexes);
yTop2 = y5(indexes);
for k=1:length(xTop2)
profile2(k) = bwimg(yTop2(k),xTop2(k ));
plot(profile2,'r-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
r4 =8*diameters/8;
x5= circleCenterX + r4 * sin(t);
y5= circleCenterY + r4 * cos(t);
bw =bw|poly2mask(x5,y5,r,c);
boundaries = bwboundaries(bw);
thisBoundary = boundaries{1};
x6=thisBoundary(:,2);
y6=thisBoundary(:,1);
indexes = y6<circleCenterY; % Only those in the upper half.
xTop3 = x6(indexes);
yTop3 = y6(indexes);
for k=1:length(xTop3)
profile3(k) = bwimg(yTop3(k),xTop3(k ));
plot(profile3,'b-','LineWidth',2 );
%grid on ;
ylim([0 2]);
axis off;
end
  4 commentaires
Zara Khan
Zara Khan le 22 Jan 2019
I have attached a picture to explain what type of output I am expecting
Jan
Jan le 22 Jan 2019
I do not get any idea, how the attached images concern the described problem. You have posted a pile of code, but it is not clear, which lines are interesting to understand, what you want to achieve. Does "cant separate all the signals" mean, that you want to separate some signals? Please elaborate this again. I know, that it is hard to do this in a foreign language, but don't give up. Explain the problem, until somebody understands it and support you to find a solution.

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Réponse acceptée

Star Strider
Star Strider le 22 Jan 2019
Modifié(e) : Star Strider le 22 Jan 2019
Try something like this using the bsxfun (link) function:
x = linspace(0, 2*pi); % Independent Variable
y = sin((0:5)'*x); % Original Signals
y = bsxfun(@plus, y, (0:size(y,1)-1)'*2); % Separated Signals
figure
plot(x, y)
grid
EDIT —
Added plot:
How can plot multiple same amplitude signals along with same y axis - 2019 01 22.png
  21 commentaires
Zara Khan
Zara Khan le 23 Jan 2019
'Profiles' are not in same length.
Star Strider
Star Strider le 23 Jan 2019
Then just do something like this:
profile_a = profile;
profile1_a = profile1 + 2;
prodile2_a = profile2 + 4;
profile3_a = profile3 + 6;
Then plot ‘profile_a’ and the others, instead.

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Plus de réponses (1)

Zara Khan
Zara Khan le 2 Fév 2019
Star Strider : Thank you. finally I am done with this. its working well.

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